An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).
The reaction is as follows:
HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH
So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms
Answer:
the radius is half the diameter
Answer:
As the amplitude of pendulum motion increases, the period lengthens, because the restoring force −mgsinθ increases more slowly than −mgθ (sinθ≅θ−θ3/3!for small angles).
Answer: B I think, I'll put my reasoning below.
Explanation:
It's not A because removing N2 would only shift the equation the opposite way.
It's not C and D because I don't think those affect the specific amount of each reactant/product produced. I think temperature only affects the speed at which the reaction is performed, which won't affect anything in this case.
Answer:
b. Loose clothing and jewelry is more likely to impede movement, or accidentally knock materials over, causing a spill or other accident.
Explanation:
Hello,
During the laboratories, a high dexterity is required, thus, such accessories, when you move or change your duty, could touch other materials or act out of your control resulting in spillages and constricting your proper movements and skills, that is why considering the lab safety policy, we must take those artifacts away from the chemistry lab.
Best regards.
