Answer:
-7.44°C
Explanation:
Calculate the molality of the solution. Use the density of the solvent(water) as a conversion factor in order to convert from millilitres of solvent to grams of solvent. Then convert grams into kilograms. Finally, use the molar mass of ethylene glycol as a conversion factor to convert from grams to moles of ethylene glycol.
m = 25.4 g C2H6O2/89.0 mL solv
= 4.6321 C10H8O
Compute the freezing-point depression.
ΔT_f=K_f*m ==> (1.86°C)*(3.9996 m)
=7.44°C
Compute the freezing point of the solution by subtracting the freezing-point depression to the freezing point of the pure solvent.
freezing point =0.0°C-ΔT_f
= -7.44°C
Its called static friction.
Answer:
b.
Explanation:
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Answer:
The temperature change is -633.15K
Explanation:
If we considered the expansion as a reversible one (to be adiabatic is one of the requirements), the work done by expansion can be written as:
Where 2 and 1 subscripts mean the final and the initial state respectively. The equation negative sign says that for an expansion of the gas, the system is making work, so the energy is going out of the system.
Using the ideal gas equation, it is possible to change volume and pressure by temperatures:
So,
This result makes sense considering that the volume increases, so it is expected that the temperature decreases.
I’m sure the answer should be E, because the rest don’t make a lot of sense the way that they’re stated
