All of the following statements about electromagnetic radiation are true except

helicopter flies an average velocity of 70 m/s2 for 10.0 seconds. What ios ther magnitude of the helicopter's displacement? answ

Inessa [10]

The uniform movement allows finding the results for the helicopter displacement during the 10 s is: 700 m

Kinematics studies the motion of bodies, finding relationships between the position, velocity and acceleration of the body, in the special case that the acceleration is zero, it is called uniform motion and is described by the equation

$v = \frac{\Delta s}{t}$

Where v is the average velocity, Ds is the displacement and t is the time

Δs = v t

They indicate that the average speed is 70 m / s and the travel time is t=10.0s

Let's calculate

Δs = 70 10.0

Δs = 700 m / s

In conclusion using the uniform movement we can find the results for the helicopter displacement is: 700 m

Learn more here: brainly.com/question/14355103

7 0

2 years ago

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help me plz answere this question plz. . . Which statement best compares momentum and kinetic energy?. . answeres plz help:. . A

ad-work [718]

B. if you double the velocity of an object, its momentum doubles. but for the same increase in velocity, the kinetic energy increases 4 times..

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3 years ago

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Three dogs (Spot, Fido, and Steinberg) are pulling on a chew toy. The chew toy is experiencing no acceleration. Spot is pulling

quester [9]

Answer:

The magnitude and direction of the force applied by Steinberg are approximately 15.192 newtons and 126.704º.

Explanation:

The chew toy is at equilibrium and experimenting three forces from three distinct dogs. The Free Body Diagram depicting the system is attached below. By Newton's Laws we construct the following equations of equilibrium: (Sp is for Spot, F is for Fido and St is for Steinberg) All forces and angles are measured in newtons and sexagesimal degrees, respectively:

$\Sigma F_{x} = F_{F}\cdot \cos \theta_{F} + F_{St,x} = 0$ (1)

$\Sigma F_{y} = F_{F}\cdot \sin \theta_{F}-F_{Sp}+F_{St,y} = 0$ (2)

If we know that $F_{F} = 20\,N$ , $F_{Sp} = 30\,N$ and $\theta_{F} = 63^{\circ}$ , then the components of the force done by Steinberg on the chewing toy is:

$F_{St,x} = -F_{F}\cdot \cos \theta_{F}$

$F_{St,x} = -(20\,N)\cdot \cos 63^{\circ}$

$F_{St, x} = -9.080\,N$

$F_{St,y} = F_{Sp}-F_{F}\cdot \sin \theta_{F}$

$F_{St,y} = 30\,N-(20\,N)\cdot \sin 63^{\circ}$

$F_{St, y} = 12.180\,N$

The magnitud of the force is determined by Pythagorean Theorem:

$F_{St} = \sqrt{F_{St,x}^{2}+F_{St,y}^{2}}$

$F_{St} =\sqrt{(-9.080\,N)^{2}+(12.180\,N)^{2}}$

$F_{St} \approx 15.192\,N$

Since the direction of this force is in the 3rd Quadrant on Cartesian plane, we determine the direction of the force with respect to the eastern semiaxis:

$\theta_{St} = 180^{\circ} + \tan^{-1} \left(\frac{F_{St,y}}{F_{St,x}}\right)$