Answer:
–8.35 m/s²
Explanation:
We'll begin by converting 104 km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
104 km/h = 104 km/h × 1 m/s / 3.6 Km/h
104 km/h = 28.89 m/s
Thus, 104 km/h is equivalent to 28.89 m/s.
Finally, we shall determine the deceleration of the car. This can be obtained as follow:
Initial velocity (u) = 28.89 m/s
Final velocity (v) = 0 m/s
Distance (s) = 50 m
Deceleration (a) =?
v² = u² + 2as
0² = 28.89² + (2 × a × 50)
0 = 834.6321 + 100a
Collect like terms
0 – 834.6321 = 100a
–834.6321 = 100a
Divide both side by 100
a = –834.6321 / 100
a = –8.35 m/s²
Thus, the deceleration of the car is –8.35 m/s².
Answer:
Matter is everything that surrounds us. It has mass and occupies a place in space. Matter can be described by measuring the value of its properties; for example: density, color, mass, volume, etc.
al ser homogenea no se puede percibir con la vista pero si se le agrega acido sulfurico la reaccion hara que el hidrogeno y el oxigeno se evaporen dejando unicamente una masa negra de carbono
No, ya que, es una mezcla homogénea, es decir, sus elementos están muy unidos mas no combinados de manera química, es posible separarlos pero con mucha dificultad, por tanto, es imposible diferenciarlos a simple vista. Se sabe que están distribuidos de manera uniforme, su estado es conocido como solución o disolución, tal como es el caso del azúcar.
Explanation:
I hope my answer serves you and that it is to your liking please give me cornita: 3
Answer:
2274 J/kg ∙ K
Explanation:
The complete statement of the question is :
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.
= mass of metal = 400 g
= specific heat of metal = ?
= initial temperature of metal = 100 °C
= mass of aluminum cup = 100 g
= specific heat of aluminum cup = 900.0 J/kg ∙ K
= initial temperature of aluminum cup = 15 °C
= mass of water = 500 g
= specific heat of water = 4186 J/kg ∙ K
= initial temperature of water = 15 °C
= Final equilibrium temperature = 40 °C
Using conservation of energy
heat lost by metal = heat gained by aluminum cup + heat gained by water
Answer:
2KI + Cl₂ → 2KCl + I₂
Explanation:
The reaction equation is given as:
KI + Cl₂ → KCl + I₂
The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;
aKI + bCl₂ → cKCl + dI₂
Conserving K : a = c
I : a = 2d
Cl : 2b = c
Now let a = 1, c = 1 , d = 
, b = , ;
Multiply through by 2;
a = 2, b = 1 , c = 2, d = 1
2KI + Cl₂ → 2KCl + I₂
