Two coaxial cylindrical conductors are shown in perspective and cross-section above. The inner cylinder has radius a = 2 cm, len
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Well idk if this helps but the formula to solve acceleration is
a=F/m=(100kg)=1.0m/s 2
a=F/m=(100kg)=1.0m/s 2
Answer:
The kinetic energy is: 50[J]
Explanation:
The ball is having a potential energy of 100 [J], therefore
PE = [J]
The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.
In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.
When the elevation is 5 [m], we have a potential energy of
This energy is equal to the kinetic energy, therefore
Ke= 50 [J]