Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
Answer:
- Calculus texts: 600
- History texts: 0
- Marketing texts: 0
Step-by-step explanation:
Each Calculus text returns $10/2 = $5 per unit of shelf space. For History and Marketing texts, the respective numbers are $4/1 = $4 per unit, and $8/4 = $2 per unit. Using 1200 units of shelf space for 600 Calculus texts returns ...
$5/unit × 1200 units = $6000 . . . profit
Any other use of units of shelf space will reduce profit.
Answer:
m∠ABD = m∠CBE ⇒ by subtracting a common angle from the given angles
Step-by-step explanation:
∵ m∠ABE = m∠CBD
∵ m∠ABD = m∠ABD + m∠DBE
∵ m∠CBD = m∠CBE + m∠EBD
∵ ∠EBD is common angle between them
∴ m∠ABD = m∠CBE
Answer:
x = 51
Step-by-step explanation:
2x + 4 + x + 23 = 180
3x + 27 = 180
3x = 153
x = 51