Answer:
The energy and the wavelength of the photon are 1.546 MeV and .
Explanation:
Given that,
Kinetic energy = 261 KeV
Planck's constant
Speed of light
Mass of electron
Charge
(A). We need to calculate the energy of the photon
Using formula of rest mass energy
Energy in eV
The total energy of photon
(B). We need to calculate the wavelength of the photon
Using formula of wavelength
Put the value into the formula
Hence, The energy and the wavelength of the photon are 1.546 MeV and .
Answer:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
Explanation:
Record your measured values of displacement and velocity for times t = 8.0 seconds and t = 10.0 seconds in the columns below.
Next, use the measured displacement and velocity values at t = 7.0 seconds and t = 9.0 seconds to interpolate the values of displacement and velocity at t = 8.0 seconds.
Use the following formula to interpolate and extrapolate. Remember, x and y here represent values on the x and y axes of the graph. The x values will really be time and the y values will be either displacement (x) or velocity (vx).
This is the answer
The electrostatic force between two point charges is given by:
where
is the Coulomb's constant
q1 and q2 are the two charges
r is the distance between them
In our problem, charge 1 is
while charge 2 is
and their distance is
r=5.0 cm=0.05 m
So, the electrostatic force between them is
And the negative sign means the force is attractive, because the two charges have opposite sign.
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