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3 years ago

When an unbalanced force acts on an object,

2 answers:

6 0

When balanced forces follow up on an object, the object won't move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.

Paladinen [302]3 years ago

6 0

<h3><u>Answer;</u></h3>

The object accelerates

When an unbalanced force acts on an object,<u> the object accelerates</u>.

<h3><u>Explanation;</u></h3>

If the forces acting on a budget are balanced, the motion of the object does not change. The net force acting on the object will be zero.
<em><u>When the net force acting on an object is not zero, the forces acting on the object are unbalanced forces. Unbalanced forces cause objects to change their motion, or accelerate.</u></em>
Balanced forces on an object do not affect the motion of an object while the unbalanced forces change the motion of an object.

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A hollow cylinder with an inner radius of 5 mm and an outer radius of 26 mm conducts a 4-A current flowing parallel to the axis

bearhunter [10]

Answer:

B = 38.2μT

Explanation:

By the Ampere's law you have that the magnetic field generated by a current, in a wire, is given by:

$B=\frac{\mu_o I_r}{2\pi r}$ (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

r: distance from the center of the cylinder, in which B is calculated

Ir: current for the distance r

In this case, you first calculate the current Ir, by using the following relation:

$I_r=JA_r$

J: current density

Ar: cross sectional area for r in the hollow cylinder

Ar is given by $A_r=\pi(r^2-R_1^2)$

The current density is given by the total area and the total current:

$J=\frac{I_T}{A_T}=\frac{I_T}{\pi(R_2^2-R_1^2)}$

R2: outer radius = 26mm = 26*10^-3 m

R1: inner radius = 5 mm = 5*10^-3 m

IT: total current = 4 A

Then, the current in the wire for a distance r is:

$I_r=JA_r=\frac{I_T}{\pi(R_2^2-R_1^2)}\pi(r^2-R_1^2)\\\\I_r=I_T\frac{r^2-R_1^2}{R_2^2-R_1^2}$ (2)

You replace the last result of equation (2) into the equation (1):

$B=\frac{\mu_oI_T}{2\pi r}(\frac{r^2-R_1^2}{R_2^2-R_1^2})$

Finally. you replace the values of all parameters:

$B=\frac{(4\pi*10^{-7}T/A)(4A)}{2\PI (12*10^{-3}m)}(\frac{(12*10^{-3})^2-(5*10^{-3}m)^2}{(26*10^{-3}m)^2-(5*10^{-3}m)^2})\\\\B=3.82*10^{-5}T=38.2\mu T$

hence, the magnitude of the magnetic field at a point 12 mm from the center of the hollow cylinder, is 38.2μT

8 0

3 years ago

Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of

allochka39001 [22]

Answer:

ni = 2.04e19

Explanation:

we know that in semiconductor like intrinsic, when electron leave the band, it leave a hole in valence band so we have

n = p = ni

from intrinsic carrier concentration

$\sigma = n\left | e \right | \mu_e + n\left | e \right | \mu_h$

$\sigma = ni\left | e \right | \mu_e + ni\left | e \right | \mu_h$

$\sigma = ni \left | e \right | ( \mu_e + \mu_h)$

1.7 = ni * 1.6*10^{-19} * (.35 + .17)

ni = 2.014 *10^{19} m^{-3}

ni = 2.04e19

5 0

3 years ago

Which of these is emitted during beta decay ?

satela [25.4K]

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

4 0

3 years ago

Read 2 more answers

Which of the following statements are true?Check all that apply.-In a uniform electric field, the field lines are straight, para

TiliK225 [7]

Answer:

1-In a uniform electric field, the field lines are straight, parallel, and uniformly spaced this statement is true.

2-Electric field lines near positive point charges radiate outward. this statement is also true.

3-The electric force acting on a point charge is proportional to the magnitude of the point charge. this statement is true as well.

Explanation:

the electric field created by a point charge is defined by E=KQ/r^2 where k is constant, q is magnitude of charge and r is the distance away from the point charge so the electric filed is distance dependent and can not be constant at all distances.

electric field lines near a negative point charge are directed radially inward because negative charge attracts the field and is not clockwise.

6 0

3 years ago

How does the egg drop project apply to newtons 3 laws of motion

iren2701 [21]

The reason why it relates to the newtons 3 laws of motion because the first law of motion states that every object will stay at rest unless it's moved by an unbalanced force which is your hand. The second one states that <span> the velocity of an object changes when it is subjected to an external force meaning it's used by the equation that is commonly used for which is F=M*A. The way it relates to the second law because you are adding force some way or another, the mass is the egg and the acceleration is the drop of the egg while it free falls. And the last one, for a reaction there is always an equal or opposite reaction and the opposite reaction is the floor because it's going against the egg causing it to crack. If it was with the egg, it would have a soft, smooth landing.</span>

8 0

4 years ago