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Reika [66]
3 years ago
13

When an unbalanced force acts on an object,

Physics
2 answers:
Gwar [14]3 years ago
6 0
When balanced forces follow up on an object, the object won't move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.
Paladinen [302]3 years ago
6 0
<h3><u>Answer;</u></h3>

The object accelerates

When an unbalanced force acts on an object,<u> the object accelerates</u>.

<h3><u>Explanation;</u></h3>
  • If the forces acting on a budget are balanced, the motion of the object does not change. The net force acting on the object will be zero.
  • <em><u>When the net force acting on an object is not zero, the forces acting on the object are unbalanced forces. Unbalanced forces cause objects to change their motion, or accelerate.</u></em>
  • Balanced forces on an object do not affect the motion of an object while the unbalanced forces change the motion of an object.
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A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the positive +z-direction. The magnetic field is unif
marysya [2.9K]

The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:

  • In Cartesian form  F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction F = 2.53 N and θ = 346.2º

Given parameters.

  • Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
  • The current i = 9.00 A in the positive direction of the z axis.
  • The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T

To find.

  • Magnetic force.

The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.

          F = i L x B

Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.

The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.

         F= i |L| \left[\begin{array}{ccc}i&j&k\\L_x&L_y&L_z\\B_x&B_y&B_z\end{array}\right]  

Let's calculate.

       F= 9.00  \ 0.25 \ \left[\begin{array}{ccc}i&j&k\\0&0&1\\-0.242&-0.985&-0.336\end{array}\right]  

       F = 2.26 \ ( - 1 B_y i  \   + 1 B_x j  \ )  

       F = 2.5 (0.985 i ^ - 0.242 j ^)

       F = ( 2.46 i ^ - 0.605 j^ ) N

To find the magnitude we use the Pythagorean theorem.

        F = \sqrt{F_x^2 + F_y^2}  

        F = \sqrt{2.46^2 + 0.605^2}  

        F = 2.53 N

Let's use trigonometry for the direction.

        Tan θ ’= \frac{F_y}{F_x}  

        θ'= tan⁻¹ \frac{F_y}{F_x}  

        θ'= tan⁻¹1 (\frac{-.605}{2.46} )

        θ’= -13.8º

To measure this angle from the positive side of the x-axis counterclockwise.

        θ = 360- θ'

        θ = 360 - 13.8

        θ = 346.2º

In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:

  • In Cartesian form    F = 2.46 i ^ - 0.605 j ^
  • In the form of magnitude and direction  F = 2.53 N and θ = 346.2º

Learn more here:  brainly.com/question/2630590

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3 years ago
Calculate the equivalent resistance of the circuit below.
expeople1 [14]

Answer:

30Ω

Explanation:

To calculate the equivalent resistance in the circuit, do the following:

Step 1:

10Ω and 20Ω are in series connection. Therefore their equivalent is: 10 + 20 = 30Ω

Step 2:

The equivalent resistance (30Ω) obtained from the above is in parallel connection with 30Ω resistance shown in the diagram above.

Therefore their equivalent is given by:

1/30 + 1/30 = 2/30 = 1/15.

Now invert to obtain the equivalent

Therefore, the equivalent is 15Ω

Step 3:

Determination of the overall equivalent of the resistance of the circuit.

The new equivalent resistance 15Ω obtained above is in series connection with 15Ω resistance in the diagram above.

Therefore their equivalent is given by:

15Ω + 15Ω = 30Ω

Therefore, the equivalent resistance in the circuit is 30Ω

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Explanation:

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