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Georgia [21]
3 years ago
12

Comparing the energies of the following intermolecular forces on a kJ/mol basis, which would normally have the highest energy (i

.e., be the strongest force)?
A) ion-induced dipole

B) dipole-induced dipole

C) ion-dipole

D) dipole-dipole

E) dispersion
Chemistry
1 answer:
Kay [80]3 years ago
8 0

Answer: option C, ion-dipole

Explanation:

Since the order of intermolecular forces is as follows

Ion-dipole > Hydrogen bonding> Dipole-dipole> dipole -induced dipole> ion induced dipole> dispersion forces

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How many miles of NaCl are in 250 mL of a 0.4 M solution?​
creativ13 [48]

Answer:

There are 0.1 moles of solute in 250 mL of 0.4 M solution.

Explanation:

First, recognize that the molar concentration tells you how many moles of the solute are present in one liter of solution. In a 0.4 M solution, there are 0.4 moles of solute in every liter of solution. You can determine the number of moles of solute in 250 mL of the solution using dimensional analysis.

250 ml . 1L/1000 L . 0.4mol / 1L

Units of liters and milliliters cancel, leaving you with a final answer in units of moles, at 0.1 mol.

8 0
3 years ago
Consider the market for paper. Let market demand be given by inverse demand function P d (Q) = 60 − Q, where Q is tons of paper
MakcuM [25]

Answer:

See explaination

Explanation:

Demand for paper is given below:

P(Q)=60-Q,

Number of paper mills=20

The cost curve for firm is given below:

C(Q)=10Q2

The external cost in terms of pollution down river by production of paper is given below:

EC(Q)=10Q2

a. The optimal level of paper production by market can be calcuated by equating MC=P

20Q=P

Q=P/20

b. The optimal level of paper production by market can be calcuated by equating MC=P.

MC=20Q

60-(20Q)=20Q

Q=60/40

Q=1.5

Total quanity by 20 firms will be 1.5*20=30

c. The socially efficient level of paper output is calcuated below:

MC+EC'=20Q+20Q

60-(20Q)=40Q

Q=60/60

Q=1

Total quanity by 20 firms will be 1*20=20

The price will be P=60-20=40

d, The deadweight loss occurs as market price increases and quantity decreases due to the external cost . The deadweight loss is calcuated below:

DWL=(1/2)*change in price* change in quantity

=(1/2)*10*10=50

e. 20 firms merged into one firm to make monopoly firm. The cost function for the monopoly is given below:

Cm(Q)=20*10(Q/20)2

The marginal cost for the monopoly firm will be

MCm=Q

The marginal revenue for the firm is 60-2Q

For optimal output MR is equated to MC

60-2Q=Q

Q=20

P=40.

The monopoly outcome is below the perfect competition outcome and price is higher in comparison to perfect competition. The monopoly outcome is same as socially efficient outcome.

The total surplus for this outcome is sum of consumer surplus and producer surplus and subtraction of external cost

TS=CS+PS-EC

=(1/2)*20*20+(1/2)*40*20-10(20)2

=600-4000=-3400

Due to the external effects the total surplus to the society is negative. In perfect competition this effect is not considered and output produced is high therefore, the external cost will be higher with higher output leading to higher negative social surplus. Generally the monopoly outcome reduces the total social surplus but in case of externality, the monopoly total surplus is higher than the perfect competition.

3 0
3 years ago
Find the mass in grams of 0.75 moles of magnesium (Mg).
Lady bird [3.3K]

Answer:

18.22874999999973

I recommend you to round the nearest 1 d.p

Explanation:

<em>h</em><em>a</em><em>v</em><em>e</em><em> </em><em>a</em><em> </em><em>g</em><em>r</em><em>e</em><em>a</em><em>t</em><em> </em><em>d</em><em>a</em><em>y</em><em>!</em>

3 0
3 years ago
Read 2 more answers
"How many formula units are there in sample of copper(II) sulfate that has
babymother [125]

Answer: 1.23\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{32.5g}{160g/mol}=0.203moles

1 mole of CuSO_4 contains 6.023\times 10^{23} of formula units

Thus 0.203 mole of CuSO_4 contains =\frac{6.023\times 10^{23}}{1}\times 0.203=1.23\times 10^{23} of formula units

8 0
4 years ago
What is the mass of 5.50 mol of iron
Bingel [31]

Answer:

306g

Explanation:

m=5.5*56=308g

7 0
3 years ago
Read 2 more answers
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