Information I learned from history class Education in the 1950's expanded from previous decades. They no longer focused purely on reading, writing and arithmetic. History and science became a main part of the cirriculum. Also, enrollment skyrocketed as the baby-boomers began enrolling in elementary school. One interesting thing that categorized this generation was the presence of fallout tests. Schools would require the students to go through a fake atomic bomb attack in which they would hide under their desks (which was completely pointless in protecting them from radiation, it was more of an emotional security for the parents and teachers, but scared the hell out of the students). Socially, children were taught to conform and to be normal. Standing out or questioning authority was bad. Sex was taught, though minimally. They explained the penis and vagina. Sexually transmitted diseases were focused on greatly so as to "scare" the students out of premarital sex.
Moving without acceleration
<h2>
Answer: The "raising pudding" atomic model</h2>
Explanation:
<u>During the 19th century the accepted atomic model, was Dalton's atomic model</u>, which postulated the atom was an <u>"individible and indestructible mass".</u>
However, at the end of 19th century J.J. Thomson began experimenting with cathode ray tubes and found out that atoms contain small subatomic particles with a negative charge (later called <u>electrons</u>). This meant the atom was not indivisible as Dalton proposed. So, Thomson developed a new atomic model.
Taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons (with negative charge) were immersed in the atom of positive charge that counteracted the negative charge of the electrons. <u>Just like the raisins embedded in a pudding or bread.
</u>
That is why this model was called the <u>raisin pudding atomic model.</u>
Answer:
0.73 m/s
Explanation:
From Newton second law of motion,
I = m(v-u)...................... Equation 1
Where I = Impulse, m = mass of the person, v = final velocity, u = Initial velocity.
make v the subject of the equation
v =(I/m)+u................. Equation 2
Note: u = 0 m/s as the person is falling from an height.
Given: I = 55 Ns, m = 75 kg, u = 0 m/s
Substitute into equation 2
v = 55/75
v = 0.73 m/s
Answer:
2a.) Wavelength = 1.8 m
2b.) F = 66.67 Hz
3a.) Find the attached file
3b.) Wavelength = 0.6 m
Explanation:
Given that the
Length L = 0.9m
Wavelength (λ) = 2L/n
Where n = number of harmonic
If n = 1, then
Wavelength (λ) = 2L = 2 × 0.9 = 1.8 m
b.)
If waves travel at a speed of 120m/s on this string, what is the frequency
associated with the longest wave (first harmonic)?
Given that V = 120 m/s
V = Fλ
But λ = 2L, therefore,
F = V/2L
F = 120/1.8
F = 66.67 Hz
3. b.) If there are two node, the position will be in 3rd position which is 3rd harmonic
Using the same formula,
Wavelength (λ) = 2L/n
Where n = 3
Wavelength (λ) = 2 × 0.9/3
Wavelength (λ) = 0.6 m
