Answer:
-7.44°C
Explanation:
Calculate the molality of the solution. Use the density of the solvent(water) as a conversion factor in order to convert from millilitres of solvent to grams of solvent. Then convert grams into kilograms. Finally, use the molar mass of ethylene glycol as a conversion factor to convert from grams to moles of ethylene glycol.
m = 25.4 g C2H6O2/89.0 mL solv
= 4.6321 C10H8O
Compute the freezing-point depression.
ΔT_f=K_f*m ==> (1.86°C)*(3.9996 m)
=7.44°C
Compute the freezing point of the solution by subtracting the freezing-point depression to the freezing point of the pure solvent.
freezing point =0.0°C-ΔT_f
= -7.44°C
Answer:
47 ms
well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.
The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]
so t = sqrt(2*100/9.8) = 4.52s.
The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s
The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.
so the final velocity is = sqrt(44.3^2 + 14.4^2) = 47.ms
To solve this problem we will apply Newton's second law and the principle of balancing Forces on the rope. Newton's second law allows us to define the weight of the mass, through the function
Here,
m = mass
a = g = Gravitational acceleration
Replacing we have that the weight is
Since the rope is taut and does not break, the net force on the rope will be zero.
Therefore the tensile force in the rope is 98N
Answer:
The skier's change in velocity is 7.69 meters per second.
Explanation:
The Newton's second law tells force is equal to the change on the linear momentum of a body:
If we approximate the differential 
to 
:
Using that linear momentum is mass times velocity:
Solving for 
:
