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3 years ago

A solution is made using 199.7 g of toluene and 80 g of benzene. What is the molality of the tolunene in the solution?

Chemistry

1 answer:

olga nikolaevna [1]3 years ago

6 0

Answer:

The molality of toluene is 7.748 molal

Explanation:

Step 1: Data given

Mass of toluene = 199.7 grams

Mass of benzene = 80.0 gram

Molar mass of benzene = 78.11 g/mol

Molar mass of toluene = 92.14 g/mol

Step 2: Calculate total mass

Total mass = mass of toluene + total benzene

Total mass = 199.7 grams + 80.0 grams

Total mass = 279.7 grams = 0.2797 kg

Step 3: Calculate moles of toluene

Moles toluene = mass toluene / molar mass toluene

Moles toluene = 199.7 grams / 92.14 g/mol

Moles toluene = 2.167 moles

Step 4: Calculate molality of toluene

Molality toluene = moles / mass solution

Molality = 2.167 moles / 0.2797 kg

Molality = 7.748 molal

The molality of toluene is 7.748 molal

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belka [17]

Answer:

a) 965,1 lbf

b) 4,5 kg

c) 1,33 * 10^6 dynes

Explanation:

Mass of an object refers to the amount of mattter it cotains, it can be expressed it gr, kg, lbm, ton, etc.

Weight of an object refers to a force, and is the measurement of the pull of gravitiy on an object. It may be definide as the mass times the acceleration of gravity.

w=mg

In Planet Earth, the nominal "average" value for gravity is 9,8 m/s² (in the International System) or 32,17 ft/s² (in the FPS system).

To solve this problem we'll use the following conversion factors:

1 lbf = 1 lbm*ft/s²

1 N = 1 kg*m/s²

1 dyne = 1 gr*cm/s² and 1 N =10^5 dynes

1 ton = 907,18 kg

1 k = 1000 gr

a) m = 30 lbm

$w = 30 lbm * 32,17 ft/s^{2} = 965, 1 \frac{lmb*ft}{s^{2} } = 965,1 lbf$

b) w = 44 N

First, we clear m of the weight equation and then we replace our data.

$m = \frac{w}{g} = \frac{44 N}{9,8 \frac{m}{{s}^{2}} } = 4,5 kg$

c) m = 15 ton

$m=15 ton * \frac{907,18 kg}{1 ton} = 13607,7 kg \\ w = mg = 13607,7 kg * 9,8 m/s2 = 133355,5 N * \frac{10^{5} dynes }{1 N} = 1,33 * 10^{6}dynes$

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in the periodic table, a set of properties repeats from row to row

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Explanation:

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A sample of methane occupies a volume of 174.0 mL at 25 C and exerts a pressure of 1030.0 mmHg if the volume of the gas is allow

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Answer:

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Explanation:

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We convert the unit Celsius into Kelvin (0 ° C = 273K) and the unite mmHg into atm (760mmHg=1 atm):

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