Answer: Combustion
Explanation:
Methane gas or natural gas is the hydrocarbon that reacts with oxygen as shown below: CH4 + 2O2 → CO2 + 2H2O There are two types of combustion reactions: complete and incomplete combustion. Therefore there are four products, carbon dioxide, water, carbon, and carbon monoxide.
Answer:
The A option is the correct answer: Non-native disulfide bonds form after beta-mercaptoethanol is removed, so the protein cannot refold correctly
Explanation:
Beta-Mercaptoehanol is responsible to reduce the four disulfide bonds present in ARNase; Urea deals with non covalente bonds. In presence of both ARNase is denatured.
If Urea is first removed by dialysis, and later is removed Beta-Mercaptoethanol, the enzyme recovers ist activity.
If Beta-Mercaptoethanol is first removed, disulfide bonds different from native use to be formed. As a result ARNase is not an active enzyme
To the picture I will be attaching, the intervals in which the potential energy decrease and the average kinetic energy will remain constant is on the interval or DE and BC, so the answer in this is the interval in which DE and BC is at constant because they are still straight line.
Answer:
I think option (D)is not true
Answer:
a) if the liquid is not vaporized completely, then the condensed vapor in the flask contains the air which is initially occupied before the liquid is heated. When calculating the molar mass of the vapor the moles of air which are initially present are not excluded, so that the molar mass of the vapor would be an increase in value.
b) While weighing the condensed vapor, the flask should be dried. If the weighing flask is not dried then the water which is layered on the surface of the flask is also added to the mass of the vapor. Therefore, the mass of the vapor that is calculated would be increase.
c) When condensing the vapor, the stopper should not be removed from the flask, because the vapor will escape from the flask and a small amount of vapor will condense in the flask. Therefore, the mass of the condensed vapor would be In small value.
d) If all the liquid is vaporized, when the flask is removed before the vapor had reached the temperature of boiling water, then the boiling
temperature of that liquid would be lower than that of the boiling temperature of the water.Therefore, the liquid may have more volatility.
