Answer is: 7,826 kg of cryolite.
Chemical reaction: Al₂O₃ + 6NaOH + 12HF → 2Na₃AlF₆ + 9H₂<span>O.
m(</span>Al₂O₃) = 12,1 kg = 12100 g.
n(Al₂O₃) = m(Al₂O₃) ÷ M(Al₂O₃).
n(Al₂O₃) = 12100 g ÷ 101,96 g/mol = 111,86 mol; limiting reactant.
m(NaOH) = 60,4 kg = 60400 g.
n(NaOH) = 60400 g ÷ 40 g/mol.
n(NaOH) = 1510 mol.
m(HF) = 60,4 kg = 60400 g.
n(HF) = 60400 g ÷ 20 g/mol = 3020 mol.
From chemical reaction: n(Al₂O₃) : n(Na₃AlF₆) = 6 : 2.
n(Na₃AlF₆) = 2 ·111,86 mol ÷ 6 = 37,28 mol.
m(Na₃AlF₆) = 37,28 mol · 209,94 g/mol.
m(Na₃AlF₆) = 7826,56 g = 7,826 kg.
Answer:
Kapilari lebih kecil dan paling banyak saluran darah, mereka membentuk sambungan antara vesel yang membawa darah dari pendengaran (arteri) dan vesel yang mengembalikan darah ke jantung (urat)
Fungsi utama kapilari ialah pertukaran bahan antara sel darah dan tisu.
Veins membawa darah ke arah jantung; selepas ia melewati kapilari dan masuk melalui urat terkecil (venules).
Arteri membawa darah dari jantung; arteri sistemik mengangkut darah oksigen dari ventrikel kiri ke tisu badan.
Explanation:
(translated version)
Why blood capillary walls differ from veins and arteries
Capillaries are smaller and the most numerous of the blood vessels, they form the connection between the vessels that carry blood away from the hear (arteries) and the vessels that return the blood to the heart (veins)
The primary function of the capillaries is the exchange of materials between the blood and tissue cells.
Veins carries the blood towards the heart; after it passes through the capillaries and enters through the smallest veins (venules).
Arteries carries blood away from the heart; systemic arteries transport oxygenated blood from the left ventricle to the body tissues.
Answer:
The answer to your question is 2 molecules, or B(edg 2021).
Explanation:
edg 2021
Answer: Theoretical Yield = 0.2952 g
Percentage Yield = 75.3%
Explanation:
Calculation of limiting reactant:
n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol
pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol
- n-trans-cinnamic acid is the limiting reactant
The molar ratio according to the equation mentioned is equals to 1:1
The brominated product moles is also = 9.584*10⁻⁴ mol
Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)
= (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g
Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952
= 75.3%
PH + pOH = 14
pH
= 14 - pOH
= 14 - 11
= 3
pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M
