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mezya [45]
4 years ago
14

Please help! What is physical property and what is chemical property?

Physics
1 answer:
sladkih [1.3K]4 years ago
6 0
PHysical properties are properties that do not involve changes in the molecular level. In this case, malleability and magnetism are physical. 
Chemical properties involve changes to the substance at the molecular level or change its identity. In this case, reacting with oxygen and nonflammability is a chemical property. 
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The weight of an object on a planet depends not only on its mass but also on its distance from the planets center this table lis
Korvikt [17]

You just pointed out that the gravitational force also depends
on the distance from the planet's center. The radius of Uranus
is about 4 times the Earth's radius.  That fact alone means that
the gravitational force on the surface is 1/4² = 1/16 its value on
Earth's surface.  So increasing the planet's mass by a factor of
14 doesn't compensate for the 1/16 reduction, and the gravitational
force on Uranus is less than on Earth.

4 0
3 years ago
Two balls collide head-on on a table. The first ball has a mass of 0.50 kg and an initial velocity of 12.0 m/s. The second ball
Gnom [1K]
A is correct according to below calculation.
m₁v₀₁+m₂v₀₂=m₁v₁+m₂v₂
((m₁v₀₁+m₂v₀₂)-m₁v₁)/m₂=v₂
v₂=((.5*12-.75*16)+(.5*21.6))/.75
v₂=6.4 m/s
4 0
3 years ago
Iron filings scattered around a magnet will be most strongly drawn toward the _____.
victus00 [196]
<span>The answer is towards <span>the poles. This is because, at the poles of the magnet, the magnetic field lines get closer together hence indicating that the magnetic force is stronger here. The fields are closest together at the center of the magnet and farthest at the outside side of the magnet. </span></span>




8 0
3 years ago
Read 2 more answers
Photons with wavelength 1 pm are incident on electrons. What is the frequency of the Compton-scattered photons at an angle of 60
natali 33 [55]

Answer:

f = 1.354*10^{20} Hz

Explanation:

By conservation of linear momentum, wavelength shift due to collision of photon to electron is given by following formula

\lambda ^{'}-\lambda =\frac{h}{m_{o}c}(1-cos\theta )

where h is plank constant = 6.626*10^{-34}

c = speed of light = 3*10^{8} m/s

scattered angle  =  60 degree

m = rest mass of electron  = 9*10^{-31}

\lambda ^{'}=10^{-12} +\frac{6.626*10^{-34}}{9*10^{-31}*3*10^{8}}(1-cos60^{o} )

\lambda ^{'}= 2.215 pm

we know that 1 pm = 10^{-12}m

f = \frac{c}{\lambda ^{'}}

f = \frac{3*10^{8}}{2.215 *10^{-12}} = 1.354*10^{20} Hz

f = 1.354*10^{20} Hz

4 0
3 years ago
A particular engine has a power output of 8 kW and an efficiency of 37%. If the engine expels 10994 J of thermal energy in each
VARVARA [1.3K]

Answer:

(a) 17450.8 J (B) 1.239 sec

Explanation:

We have given power output =8 KW

Heat expelled = 10994 j

Efficiency =37% = 0.37

(A) We know that efficiency \eta =1-\frac{heat\ expelled}{heat\ input}

0.37=1-\frac{10994}{heat\ input}

Heat input =17450.8 J

(B) Work done by the engine is = 17450.8-10994=6456.8 j

Power output is given by 8 KW =8000 W

So time for each cycle is \frac{8000}{6456.8}=1.239 sec

3 0
3 years ago
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