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ryzh [129]
3 years ago
12

Two platoons line up for a tug of war. If both platoons have the same number of participants on a team, what other factor is cri

tical to either platoon's win?
A. age of men
b. height of men
c. total mass of the team
d. condition of the ground
Physics
2 answers:
Vilka [71]3 years ago
7 0

Answer:

option (c)

Explanation:

In the game of tug of war, the Newton's third law is obeyed.

One team pulls the rope in one direction and the other team pulls the rope in another direction.

As the mass of one team is more, so it is harder to pull the rope by the another team.

So, it depends on the total mass of the team.

Option (c) is correct.

sladkih [1.3K]3 years ago
4 0

Answer:

The best answer would be <u><em>C. Total mass of the team.</em></u>

Explanation:

C would be the best answer because when looking in the formula of force then the 2 factors that are inputted are mass and acceleration but in this case acceleration would most likely not have much have an effect so that leaves the factor of mass.

Hope this helped!

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I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
3 years ago
Physicists often measure the momentum of subatomic particles moving near the speed of light in units of MeV/c, where c is the sp
maxonik [38]

Answer:

kg m/s

Explanation:

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V = Voltage = \dfrac{N}{C}m

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Momentum is given by

\dfrac{MeV}{c}=\dfrac{e\times V}{c}\\\Rightarrow \dfrac{MeV}{c}=\dfrac{C\times \dfrac{N}{C}\times m}{m/s}\\\Rightarrow \dfrac{MeV}{c}=Ns\\\Rightarrow \dfrac{MeV}{c}=kg\times \dfrac{m}{s}\times s\\\Rightarrow \dfrac{MeV}{c}=kg\cdot m/s

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Rzqust [24]

Answer:

11 = 11

Explanation:

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Rom4ik [11]

Answer:

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Explanation:

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