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Ksenya-84 [330]
2 years ago
5

If the frequency of a system undergoing simple harmonic motion doubles, by what factor does the maximum value of acceleration ch

ange?
a. 4
b. 2/pi
c. 2
d. (2)^1/2
Physics
1 answer:
faltersainse [42]2 years ago
6 0

Answer:

the answers the correct one is a  4

Explanation:

The centripetal acceleration is by

           a = v² / R

angular and linear velocities are related

           v = w R

let's substitute

           a = w² R

for initial condition

           a₀ = w₀² R

suppose the initial angular velocity is wo, suppose the angular velocity doubles

           a = (2w₀)² R

           a = 4 (w₀² R)

           a = 4 a₀

when reviewing the answers the correct one is a

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Answer:7m/s

Explanation:

5.8+1.2

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A dart is thrown from 1.50 m high at 10.0 m/s toward a target 1.73 m from the ground. At what angle was the dart thrown?
Triss [41]

Answer:

The angle of projection is 12.26⁰.

Explanation:

Given;

initial position of the dart, h₀ = 1.50 m

height above the ground reached by the dart, h₁ = 1.73 m

maximum height reached by the dart, Hm = h₁ - h₀ = 1.73 m - 1.50 m= 0.23 m

velocity of the dart, u = 10 m/s

The maximum height reached by the projectile is calculated as;

H_m = \frac{u^2sin^2 \theta}{2g}

where;

θ is angle of projection

g is acceleration due to gravity = 9.8 m/s²

H_m = \frac{u^2sin^2 \theta}{2g}\\\\sin^2 \theta = \frac{H_m \ \times \ 2g}{u^2} \\\\sin^2 \theta = \frac{0.23 \ \times \ 2(9.8)}{10^2} \\\\sin ^2\theta =0.04508\\\\sin \theta = \sqrt{0.04508} \\\\sin \theta = 0.2123\\\\\theta  = sin^{-1}(0.2123)\\\\\theta  = 12.26^0

Therefore, the angle of projection is 12.26⁰.

6 0
2 years ago
5. The boiling point of mercury is lower than<br> that of alcohol.
aniked [119]

Answer:

I thinl it is I'm not sure though

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Tridil is infusing at 15 ml/hr on an infusion pump. The drug is mixed 50 mg in 500 ml D5W. How many MCG/minute is the patient re
olga nikolaevna [1]

Answer:

patient receiving drug 25 MCG/minute

Explanation:

given data

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solution

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