Answer:
2.877 m/s
Explanation:
According to the laws of conservation of linear momentum,
the momentum of the moving objects before impact is equal to the momentum of the objects after impact (Assuming no external forces were applied)
Let both players are tackled and moving in V velocity
- M and m - masses of the players
- U and u - velocities of them respectively (both velocities are towards east direction )
momentum before impact = momentum after impact
→MU + →mu = →(M+ m )v
91.5 * 2.73 + 63.5 * 3.09 = (91.5 + 63.5) * V
→V = 2.877 m/s (To East)
TheThe distance they have covered for trip is 219Km.
<h3>What do you mean by uniformly accelereted motion?</h3>
When an object is traveling in a straight line with an increase in velocity at equal intervals of time.
The total time for the trip is
T→ t1+ 22 min = t1+ 0.367 h ,where t1 is the time spent traveling at
V1= 89.5 km/ h .
the distance traveled is ∆x = V1t1=Vavg T
after applying value and calculating it we get
t1= 2.44h for a total time of
t total we get 2.81 h .
∆x =V1T1 = VavgTtotal
∆x = 77×2.81= 219 Km
to learn more about Uniform accelereted motion click here brainly.com/question/12920060
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Answer:
30×6=n
Explanation:
30 students in her class× 6 = number of students in the entire 4th grade.
Answer:
300000.01008 Pa
123.76237 m/s²
Explanation:
= Density of liquid nitrogen = 808 kg/m³
h = Depth
g = Acceleration due to gravity
P = Atmospheric pressure
Absolute Pressure is given by
Below 2 m from surface
Below 5 m from surface
Subtracting the above equations we get
The acceleration due to gravity on the planet is 123.76237 m/s²
Equating the value of g in the first equation
The atmospheric pressure on the planet is 300000.01008 Pa
Answer:
b
Explanation:
this because if force (f) are resultant cos then the point is proportional to the direction of c at greatest possible forces
