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swat32
3 years ago
13

Which techniques can help reduce the effects of tornadoes?

Physics
1 answer:
murzikaleks [220]3 years ago
3 0

Answer: 1.building storm cellars and wind-resistant structures.

3.using more radars and satellites in the area.

A tornado is a storm of wind. In tornado the high speed wind takes the form of a cone that destroys anything that comes in it's path. The following techniques can help in reducing the effects of tornadoes:

1. building storm cellars and wind-resistant structures: This will provide support and protection to the building against high speed wind currents during an event of tornado.

3.using more radars and satellites in the area: This will help in identification of origin of wind producing tornado in a region so as to create awareness about the coming calamity. This will allow people to relocate to safer place and can take preventive measures.    

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a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis
KatRina [158]
The total displacement is equal to the total distance. For the east or E direction, the distance is determined using the equation:

d = vt = (22 m/s)(12 s) = 264 m

For the west or W direction, we use the equations:
a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
t = 18.33 seconds
d = (22 m/s)(18.33 s) + 0.5(-1.2 m/s²)(18.33 s)²
d = 201.67 m

Thus,
Total Displacement = 264 m +  201.67 m = 465.67 or  approximately 4.7×10² m.
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A force F=0.12N is aplied on spring and spring elongates by 3cm . specific constant of spring ​
PilotLPTM [1.2K]

The spring constant is 4 N/m

Explanation:

When a spring is stretched/compressed by the application of a force, the relationship between the magnitude of the force applied and the elongation of the spring is given by Hooke's law:

F=kx

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k is the spring constant

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For the spring in this problem, we have:

F = 0.12 N (force applied)

x = 3 cm = 0.03 m (elongation of the spring)

Therefore, we can solve the formula for k to find the spring constant:

k=\frac{F}{x}=\frac{0.12}{0.03}=4 N/m

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4 years ago
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