Answer: 0.333 h
Explanation:
This problem can be solved using the <u>Radioactive Half Life Formula</u>:
(1)
Where:
is the final amount of the material
is the initial amount of the material
is the time elapsed
is the half life of the material (the quantity we are asked to find)
Knowing this, let's substitute the values and find
from (1):
(2)
(3)
Applying natural logarithm in both sides:
(4)
(5)
Clearing
:
(6)
Finally:
This is the half-life of the Bismuth-218 isotope
<span>Chronological essays by the definition of a chronological
meaning in order. There is an order in a specific writing. Like a history write
up from a certain happening years ago. It
is different from procedural essays because these are essays who are giving
instructions of certain set up to guide the person accordingly in doing
something to make it more accurate. Like recipes, instructions in playing, etc.
Example words that are used in chronological essays are first, second, third,
fourth, fifth, next, after, then, lastly, finally, consequently, in addition,
thus, therefore, however, etc.</span>
Correct question is;
1/0.12 = (1/0.05) + (1/d')
Answer:
d' = -1/700
Explanation:
1/0.12 = (1/0.05) + (1/d')
Let's rearrange to get;
(1/d') = (1/0.12) - (1/0.05)
(1/d') = (1/(12/100)) - (1/(5/100))
(1/d') = 100/12 - 100/5
Let's multiply through by 60 to get rid of the denominators on the right side;
> (1/d') = 500 - 1200
> (1/d') = -700
> d' = -1/700
Answer:
If you ring the doorbell and no one opens the door, you'll infer that no one is home rather than continuing to ring the doorbell to an empty house. Being able to understand this and look for another solution is another example of mental flexibility.
Explanation:
Answer:
The correct answer is option 'c': 30 AUs
Explanation:
For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

This energy per unit area is sensed by observer as intensity of the sun.
Let the initial intensity of sun at a distance
be 
Thus if the sun becomes 900 times dimmer we have

Thus the distance increases 30 times.