<span>Metalloids have the properties of metals and nonmetals.</span>
Answer:
sodium hydroxide and hydrochloric acid is the reactants
The rate of entropy change:
The rate of entropy change of the working fluid during the heat addition process is 3 kW/K
What is the Carnot cycle?
- The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession.
- The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.
The entropy of a system:
The rate of heat addition is expressed as,
Q = 
The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,

Calculation:
<u>Given:</u>
= 400K
= 1600K
W = 3600 kW
Put all the values in the above equation, and we get,
=
= 3 kW/K
The rate of entropy change is 3 kW/K
Learn more about the Carnot cycle here,
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Given:
Concentration of titrant = 0.1000 M
Volume of titrant = 45 mL
The molarity of analyte depends on the amount of the analyte present in the titrated solution. If the amount of analyte is 20 mL, then its concentration is:
45ml * 0.10 M = C analyte * 20 ml
C analyte = 0.225 M
Answer:
CH3CH2NH3+/CH3CH2NH2 would have the largest pKa
Explanation:
To answer this question we must know Kb of CH3CH2NH2 is 5.6x10⁻⁴, and for C6H5NH2 is 4.0x10⁻¹⁰. And the CH3CH2NH3+ and C6H5NH3+ are related with these substances because are their conjugate base. That means:
pKa of CH3CH2NH3+ = CH3CH2NH2; C6H5NH3+ = C6H5NH2
Also, Kw / Kb = Ka
Thus:
pKa of CH3CH2NH3+/CH3CH2NH2 is:
Kw / kb = Ka = 1.79x10⁻¹¹
-log Ka = pKa
pKa = 10.75
pKa of C6H5NH3+/ C6H5NH2 is:
Kw / kb = Ka = 2.5x10⁻⁵
-log Ka = pKa
pKa = 4.6
That means CH3CH2NH3+/CH3CH2NH2 would have the largest pKa