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Olenka [21]
3 years ago
14

Rank the following bonds in order of decreasing bond length, based on periodic trends, starting with the longest bond at the top

of the list.H-S H-I H-Se H-BI. H-I II. H-SeIII. H-BrIV. H-S
Chemistry
1 answer:
sattari [20]3 years ago
5 0

Answer:

H-BI,H-Se,H-S,H-I,H-Br

Explanation:

One thing that must be kept in mind is that atomic size increases down the group and decreases across the period. The bond lengths of species are influenced by the relative sizes of atoms or ions present in the bond.

The bonds in the answer have been arranged on basis of their decreasing atomic size because the greater the atomic size of the atoms, the greater the bond length and vice versa.

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A farmer lost most of his crops last year because of insects. This year he decided to use pesticide to kill the insects. However
Dominik [7]
The answer would be natural selection I believe
6 0
3 years ago
Aqueous solutions of lithium sulfate and calcium nitrate are mixed, forming the precipitate
Mashcka [7]

Answer:

(aq) Li2SO4 + (aq) Ca(NO3)2 --> (s) CaSO4 + (aq) 2LiNO3

Explanation:

Aqueous Lithium Sulfate is Li2SO4

Aqueous Calcium Nitrate is Ca(NO3)2

When they're mixed, we get the double displacement solution Calcium Sulfate and Lithium Nitrate.

Precipitate is solid.

We got solid Calcium Sulfate so the other solution must be aqueous.

CaSO4 (s) --> Calcium Sulfate product

LiNO3 (aq) --> Lithium Nitrate product

We balance equation now. 2 Lithiums total and 2 Nitrates total. (Cuz there are 2 on the other side, 1 here)

4 0
2 years ago
Which of the following would
nadezda [96]

Answer: A forest

Explanation:

Moss are more likely to be found in moist shady locations. They are best known for those species that carpet woodland and forest floors.

4 0
2 years ago
Find the percentage of mass in each of the element Ca ( HCO3)2 (Ca= 40, H = 1, O = 16, C= 35)​
Alex787 [66]

Answer:

% Ca = 24.69%

% H = 1.2%

% C = 14.8%

% O = 59.25%

Explanation:

The percentage by mass of each element can be calculated by dividing the mass of each element in the compound by the molar mass of the compound.

Molar mass of Ca(HCO3)2

Where; (Ca= 40, H = 1, O = 16, C= 12)

= 40 + {1 + 12 + 16(3)}2

= 40 + {13 + 48}2

= 40 + {61}2

= 40 + 122

= 162g/mol

- % mass of Ca = 40/162 × 100

= 0.2469 × 100

= 24.69%

- % mass of H = 2/162 × 100

= 0.012 × 100

= 1.2%

- % mass of C = 24/162 × 100

= 0.148 × 100

= 14.8%

- % mass of O = 96/162 × 100

= 0.5925 × 100

= 59.25%

3 0
3 years ago
A sample of CH4 is confined in a water manometer. The temperature of the system is 30.0 °C and the atmospheric pressure is 98.70
kakasveta [241]

Explanation:

The given data is as follows.

  P_{atm} = 98.70 kPa = 98700 Pa,  

      T = 30^{o}C = (30 + 273) K = 303 K

      height (h) = 30 mm = 0.03 m (as 1 m = 100 mm)

Density = 13.534 g/mL = 13.534 g/mL \times \frac{10^{6}cm^{3}}{1 m^{3}} \times \frac{1 kg}{1000 g}

                = 13534 kg/m^{3}

The relation between pressure and atmospheric pressure is as follows.

             P = P_{atm} + \rho gh

Putting the given values into the above formula as follows.

            P = P_{atm} + \rho gh

               = 98700 Pa + 13534 \times 9.81 \times 0.03 m

               = 102683.05 Pa

               = 102.68 kPa

thus, we can conclude that the pressure of the given methane gas is 102.68 kPa.

8 0
3 years ago
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