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Olenka [21]
3 years ago
14

Rank the following bonds in order of decreasing bond length, based on periodic trends, starting with the longest bond at the top

of the list.H-S H-I H-Se H-BI. H-I II. H-SeIII. H-BrIV. H-S
Chemistry
1 answer:
sattari [20]3 years ago
5 0

Answer:

H-BI,H-Se,H-S,H-I,H-Br

Explanation:

One thing that must be kept in mind is that atomic size increases down the group and decreases across the period. The bond lengths of species are influenced by the relative sizes of atoms or ions present in the bond.

The bonds in the answer have been arranged on basis of their decreasing atomic size because the greater the atomic size of the atoms, the greater the bond length and vice versa.

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4.a) Draw two Lewis structures for HCP; one where C is central and one where P is central: b) Calculate formal charge for each a
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One Hydrogen atom (H) and one Oxygen atom (O) surround the central Carbon atom (C) in the HCP Lewis structure (O). Carbon (C) and Phosphorus (P) have a triple bond, and Carbon (C) and Hydrogen (H) have a single bond.

<h3>How can you choose the ideal format for a formal charge?</h3>

The Lewis structure with the negative formal charges on the most electronegative atoms is the one to choose from when faced with a choice between numerous Lewis structures with similar formal charge distributions.

<h3>How do you determine the preferred resonance structure?</h3>

The resonance forms with the fewest non-zero formal charge atoms are selected. Resonance develops atoms that have a negative formal charge or are the most electronegative are preferred.

To know more about Lewis structure visit:-

brainly.com/question/20300458

#SPJ4

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9 months ago
I dont get it help brainlest
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Answer:

d is the answer of this question

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Read 2 more answers
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