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andreev551 [17]
3 years ago
9

Determine the volume of methane (ch 4 ) gas needed to react completely with 0.660 l of o 2 gas to form methanol (ch 3 oh).

Chemistry
1 answer:
Sloan [31]3 years ago
4 0
Balance Chemical Equation for this reaction is,

                           2 CH₄  +  O₂   →   2CH₃OH

According to this eq, 22.4 L (1 moles) of Oxygen requires 44.8 L (2 mole) CH₄ for complete reaction.
So, the volume of CH₄ required to consume 0.66 L of O₂ is calculated as,

 22.4 L O₂ required to consume  =  44.8 L CH₄
0.660 L O₂ will require                =  X L of CH₄

Solving for X,
                                                X  =  (44.8 L × 0.660 L) ÷ 22.4 L

                                                X  =  1.320 L of CH₄

Result:
            1.320 L of CH
₄ <span>gas is needed to react completely with 0.660 L of O</span>₂<span> gas to form methanol (CH</span>₃OH<span>).</span>
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In an experiment to study the photoelectric effect, a scientist measures the kinetic energy of ejected electrons as afunction of
crimeas [40]

Answer:

a) v₀ = 4.41 × 10¹⁴ s⁻¹

b) W₀ = 176 KJ/mol of ejected electrons

c) From the graph, light of frequency less than v₀ will not cause electrons to break free from the surface of the metal. Electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. Explanation is in the section below.

Explanation:

The plot for this question which is attached to this solution has Electron kinetic energy on the y-axis and frequency of incident light on the x-axis.

a) Wavelength, λ = 680 nm = 680 × 10⁻⁹ m

Speed of light = 3 × 10⁸ m/s

The frequency of the light, v₀ = ?

Frequency = speed of light/wavelength

v₀ = (3 × 10⁸)/(680 × 10⁻⁹) = 4.41 × 10¹⁴ s⁻¹

b) Work function, W₀ = energy of the light photons with the wavelength of v₀ = E = hv₀

h = Planck's constant = 6.63 × 10⁻³⁴ J.s

E = 6.63 × 10⁻³⁴ × 4.41 × 10¹⁴ = 2.92 × 10⁻¹⁹J

E in J/mol of ejected electrons

Ecalculated × Avogadros constant

= 2.92 × 10⁻¹⁹ × 6.023 × 10²³

= 1.76 × 10⁵ J/mol of ejected electrons = 176 KJ/mol of ejected electrons

c) Light of frequency less than v₀ does not possess enough energy to cause electrons to break free from the metal surface. The energy of light with frequency less than v₀ is less than the work function of the metal (which is the minimum amount of energy of light required to excite electrons on metal surface enough to break free).

As evident from the graph, electron kinetic energy remains at zero as long as the frequency of incident light is less than v₀.

d) When frequency of the light exceeds v₀, there is an increase of electron kinetic energy from zero steadily upwards with a constant slope. This is because, once light frequency exceeds, v₀, its energy too exceeds the work function of the metal and the electrons instantaneously gain the energy of incident light and convert this energy to kinetic energy by breaking free and going into motion. The energy keeps increasing as the energy and frequency of incident light increases and electrons gain more speed.

e) The slope of the line segment gives the Planck's constant. From the mathematical relationship, E = hv₀,

And the slope of the line segment is Energy of ejected electrons/frequency of incident light, E/v₀, which adequately matches the Planck's constant, h = 6.63 × 10⁻³⁴ J.s

Hope this Helps!!!

5 0
3 years ago
A chemist has a block of lead metal (density is 11.3 g/mL). The block weighs 2.10g. What is the volume if the lead block in mL?
mezya [45]

The volume of a block of lead metal that has a density of 11.3g/mL and weighs 2.10g is 0.186mL.

<h3>How to calculate volume?</h3>

The volume of a substance can be calculated by dividing the mass of the substance by its density. That is;

Volume = mass ÷ density

According to this question, a chemist has a block of lead metal (density is 11.3 g/mL). The block weighs 2.10g.

Volume = 2.10g ÷ 11.3g/mL

Volume = 0.186mL

Therefore, the volume of a block of lead metal that has a density of 11.3g/mL and weighs 2.10g is 0.186mL.

Learn more about volume at: brainly.com/question/18670654

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Cuando aumenta la temperatura dentro de un recipiente cerrado que contiene un gas este se expande/comprime por que las partícula
Evgesh-ka [11]

Answer:

expande

forman se alejan

Explanation:

Según las leyes de los gases ideales;

La ley de Charles establece que el volumen de una masa dada de gas ideal es directamente proporcional a su temperatura a la presión simultánea.

Esto significa que cuando se calienta una masa dada de gas ideal, el gas se expande y las moléculas de gas se alejan unas de otras de acuerdo con la ley de Charles.

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A rapidly falling object at a high altitude has _____
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Arte-miy333 [17]

Answer:

-1

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