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andreev551 [17]
3 years ago
9

Determine the volume of methane (ch 4 ) gas needed to react completely with 0.660 l of o 2 gas to form methanol (ch 3 oh).

Chemistry
1 answer:
Sloan [31]3 years ago
4 0
Balance Chemical Equation for this reaction is,

                           2 CH₄  +  O₂   →   2CH₃OH

According to this eq, 22.4 L (1 moles) of Oxygen requires 44.8 L (2 mole) CH₄ for complete reaction.
So, the volume of CH₄ required to consume 0.66 L of O₂ is calculated as,

 22.4 L O₂ required to consume  =  44.8 L CH₄
0.660 L O₂ will require                =  X L of CH₄

Solving for X,
                                                X  =  (44.8 L × 0.660 L) ÷ 22.4 L

                                                X  =  1.320 L of CH₄

Result:
            1.320 L of CH
₄ <span>gas is needed to react completely with 0.660 L of O</span>₂<span> gas to form methanol (CH</span>₃OH<span>).</span>
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Answer:

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Under that assumption, the heat released by the chemical reaction is equal to the heat absorbed by the system.

1. Heat absorbed by the system:

Use the equation Heat = Q = m × C × ΔT, with:

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Q = 126g × 4.186J/gºC × 3.70ºC = 1,951.5J

<em><u></u></em>

<em><u>2. Enthalpy of the reaction</u></em>

The enthalpy must be reported in kJ/mol.

Then, convert juoles to kilojoules, dividing by 1,000; and divide by 2.00 moles, which is the amount of compound that reacted:

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Round to <em>3 significant figures</em>: 0.976 kJ/mol

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