The balanced chemical reaction is given as follows:
<span>2 KClO3(s) → 2 KCl(s) + 3 O2(g)
The starting amount of the reactant are given above. These values would be used for the calculations. We do as follows:
</span>2.72 g KClO3 (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 1.06 g O2
<span>
0.361 g KClO3 </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.14 g O2
<span>
83.6 kg KClO3 (1000g / 1kg) </span>(1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 3275.76 g O2
<span>
22.5 mg KClO3</span> (1 g / 1000 mg) (1 mol / 122.50g )( 3 mol O2 / 2 mol KClO3 ) ( 32 g O2 / 1 mol O2 ) = 0.009 g O2
Answer:
23
Explanation:
we do not care about electrons, so 11 + 12 = 23
Answer:
hope its help you
Explanation:
2.600 × 10^-5 × 6.100 × 10^-5 = 1.586 × 10-9
Answer:
New temperature = 546 K
Explanation:
Given that,
Initial volume, V = 200 L
Initial temperature, T = 273 K
We need to find the new temperature if the volume is doubled.
The relation between temperature and volume is direction. If volume is doubled, it means the temperature gets also doubled.
New temperature of the gas = 2(273) = 546 K
