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Veseljchak [2.6K]
2 years ago
9

Explain how a substances flammability can indicate a chemical change.

Chemistry
1 answer:
Marat540 [252]2 years ago
4 0

Answer:

This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.

Explanation:

May I have brainliest please? :)

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What type of compound does the formula CuCl2 represent?<br> A) ionic salt<br> B) covalent molecule
Salsk061 [2.6K]

Answer: A) ionic salt

Explanation: Chlorine has a high electronegativity of 3.0. Copper like most metals has a low electronegativity, So the bonding is ionic making the compound an ionic salt.

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3 years ago
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What's the percentage of ZnF2
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3 years ago
A saturated solution of calcium hydroxide contains 1.85 g of solute in 100. mL of solution. What is its molarity
Leona [35]

Answer:

M=0.250M

Explanation:

Hello!

In this case, since the molarity of a solution is computed by dividing the moles of solute by the volume of solution in liters, we first need to compute the moles of solute knowing that the molar mass of calcium hydroxide is 74.1 g/mol as follows:

n=1.85g*\frac{1mol}{74.1g}=0.0250mol

Next, since the 100-mL solution is also expressed in liters by 0.100 L, we directly compute the molarity as shown below:

M=\frac{0.0250mol}{0.100L}\\\\M=0.250M

Which is expressed in molar units that are mol/L.

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8 0
3 years ago
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6 0
2 years ago
Water has a boiling point of 100.0°C and a Kb of 0.512°C/m. What is the boiling
Neko [114]

Answer:

104.352°C

Explanation:

Data Given:

Boiling point of water = 100.0°C

Kb (boiling point constant = 0.512°C/m

Concentration of the Mg₃(PO₄)₂ = 8.5 m

Solution:

Formula Used to find out boiling point

               ΔTb = m.Kb . . . . . . (1)

where

               ΔTb = boiling point of solution - boiling point of water

So,

we can write equation 1 as under

               ΔTb = Tb (Solution) -Tb (water)

As we have to find out boiling point so rearrange the above equation

              Tb (Solution)  = m.Kb + Tb (water) . . . . . . . (2)

Put values in Equation 2

            Tb (Solution)  = (8.5 m x 0.512°C/m ) + 100.0°C

            Tb (Solution)  = 4.352 + 100.0°C

            Tb (Solution)  = 104.352°C

so the boiling point of Mg₃(PO₄)₂  8.5 m solution =  104.352°C

3 0
3 years ago
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