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AysviL [449]
3 years ago
10

On a spinning ride at the fair, it is inertia that keeps you moving in a circle. true or false​

Physics
1 answer:
lions [1.4K]3 years ago
6 0

False, the inertia does not keep us moving in a circle on a spinning ride at the fair.

Answer: Option B

<u>Explanation: </u>

Inertia is the resisting force of any object which resists in change in their state. If an object is moving the inertia will act in opposing direction to the force acting on the object stopping its motion.

Similarly, if an object resembles at rest, then the inertia will be acting against the force tending to move that stationary object. So, on a spinning ride at fair, when a person sits there, the inertia acting on the person will prevent the person to falling down from the fair and not in moving in a circle.

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The magnetic field lines of a bar magnet spread out from the north end to the south end. South end to the north end. Edges to th
Gwar [14]
<h3><u>Answer;</u></h3>

the north end to the south end.

<h3><u>Explanation;</u></h3>
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  • A magnetic field refers to  the area surrounding a magnet where a force is exerted on certain objects. These lines are spread out of the north end of the magnet.
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3 0
3 years ago
Read 2 more answers
Which officeholders are elected by the electoral college
NikAS [45]

Answer:Electoral Vote

Explanation:i did it before

4 0
2 years ago
A material that can be hit without shattering is?<br> viscous, flammable, hard, malleable
nika2105 [10]
Malleable

Malleability is a property of matter, that’s specializes in metals, in which these metals can be bended, twisted or formed into a thinner sheets, and not being able to shatter to pieces instead it can be formed into a new shape. Unlike the other three, take for instance hardness. If a hard object such as wood for example when used with an axe it breaks and it is lead to smithereens. Flammable like is when applied to fire can dramatically explode when hit it obviously breaks.



3 0
2 years ago
We know the frequency range of certain sounds are: 400-560 Hz, what are the ranges of wavelength in meters when the signal trans
Ksivusya [100]

Answer:

Range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

Explanation:

We have given range of frequency is 400-560 Hz

Speed of the light c=3\times 10^8m/sec

We have to find the range of the wavelength of signal transmitted

Ween know that velocity is given by v=\lambda f, here \lambda is wavelength and f is frequency

So for 400 Hz frequency wavelength will be \lambda =\frac{c}{f}=\frac{3\times 10^8}{400}=7.5\times 10^5m

And wavelength for frequency 560 Hz \lambda =\frac{c}{f}=\frac{3\times 10^8}{560}=5.35\times 10^5m

So range of wavelength will be 5.35\times 10^5m to 7.5\times 10^5m

8 0
3 years ago
A horizontal uniform bar of mass 2.7 kg and length 3.0 m is hung horizontally on two vertical strings. String 1 is attached to t
Jlenok [28]

Answer:

14.36 N

Explanation:

T_{1} = Tension in string 1

T_{2} = Tension in string 2

m_b = mass of the bar = 2.7 kg

W_b = weight of the bar

weight of the bar is given as

W_b = m_{b} g = (2.7) (9.8) = 26.46N

m_m = mass of the bar = 1.35 kg

W_m = weight of the monkey

weight of the monkey is given as

W_m = m_{m} g = (1.35) (9.8) = 13.23N

Using equilibrium of torque about left end

W_{m} (AB) + W_{b} (AB) = T_{2} (AC)\\W_{m} (AB) + W_{b} (AB) = T_{2} (AD - CD)\\(13.23) (1.5) + (26.46)(1.5) = T_{2} (3 - 0.65)\\\\T_{2} = 25.33 N

Using equilibrium of force in vertical direction

T_{1} + T_{2} = W_{b} + W_{m}\\T_{1} + 25.33 = 26.46 + 13.23\\T_{1} = 14.36 N

7 0
3 years ago
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