Answer:
Wavelength of light in film (let y = lambda)
y = 500 nm / (4/3) = 375 nm
There will be a phase change at the air/film interface (not the other side)
S = 4 t thickness of film = S/4 where S equals 1 wavelength
This is because of the phase change at one surface
375 nm = 4 * t
t = 93.8 nm
Uranium-238 undergoes alpha decay. Therefore, uranium-238 will
A. Remain stable
B. Stay the same element
C. Release charged particles and no energy
<u>D. None of the above</u>
The actual answer is that it will change into a different element altogether.
(b) The Planck time is given as
T=
=5.39×
of the same order of magnitude as the ultra hot epoch
<h3>What exactly is Planck Time?</h3>
- The Planck time is the fundamental unit of time in the Planck Unit system. It has the following worth:
- =5.39×
- Measurements of time in SI units are made in seconds (usually given the symbol s). Although measuring the time it takes an athlete to sprint 100 meters or the length of a phone call in seconds is convenient in everyday life, it becomes less practical when discussing the sequence of events that occurred in the very early Universe (such as the onset of inflation that occurred 10-35s after the Big Bang).
- The entire geometry of spacetime predicted by general relativity breaks down at this scale. As a result, to describe the laws of physics on such scales, an as-yet undiscovered theory combining general relativity and quantum mechanics is required. As a result, our current descriptions of the Universe's early evolution begin at =5.39× seconds after the Big Bang.
To learn more about Planck Time refer to
brainly.com/question/26117248
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Answer:
The total distance traveled is 736 m
Solution:
According to the question:
Initial velocity, v = 0
(since, the car is starting from rest)
Time taken, t = 8 s
Now, the distance covered by it in 8 s is given by the second eqn of motion:
Now, to calculate the velocity, we use eqn 1 of motion:
v' = v + at
v' = 0 + 4(8) = 32 m/s
Now, the distance traveled by the car with uniform velocity of 32 m/s for t' = 19 s:
distance, d' = v't'
Total distance traveled = d + d' = 128 + 608 = 736 m
Answer:
Explanation:
Horizontal displacement
x = 120 t
Vertical position
y = 3610 - 4.9 t²
y = 0 for the ground
0 = 3610 - 4.9 t²
t = 27.14 s
This is the time it will take to reach the ground .
During this period , horizontal displacement
x = 120 x 27.14 m
= 3256.8 m
So packet should be released 3256.8 m before the target.