<span>The correct answer is "velocity, height". Kinetic energy is affected by: mass and velocity, while potential energy by: mass, gravity and height (or "position"). Considering these combinations, only the third choice is the correct one: a) position, gravity describe only potential energy, B) gravity, position describe only potential energy, C) velocity, height describe respectively kinetic and potential energy, D) height, velocity would respectively describe potential energy first and then kinetic energy, it is in the wrong order, thus the correct answer is C.</span>
we assume the acceleration is constant. we choose the initial and final points 1.40s apart, bracketing the slowing-down process. then we have a straightforward problem about a particle under constant acceleration. the initial velocity is v xi =632mi/h=632mi/h( 1mi 1609m )( 3600s 1h )=282m/s (a) taking v xf =v xi +a x t with v xf =0 a x = t v xf −v xf = 1.40s 0−282m/s =−202m/s 2 this has a magnitude of approximately 20g (b) similarly x f −x i = 2 1 (v xi +v xf )t= 2 1 (282m/s+0)(1.40s)=198m
Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.
Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
I feel like it’s Boyle’s Law, correct me if I’m wrong .
