When a parallel beam of light passes through a convex lens, the rays become farther from one another when the come out. This process of rays is called ''to diverge''. The concave lens makes rays of light diverge, so it is called diverging lens.
Answer:
Explanation:
Surface charge density, σ = 9 μC/m² = 9 x 10^-6 C/m²
According to the Gauss theorem,
Electric field due to the sheet is given by
![E = \frac {\sigma }{2\epsilon _{0}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%20%7B%5Csigma%20%7D%7B2%5Cepsilon%20_%7B0%7D%7D)
![E = \frac{9\times 10^{-6}}{2\times 8.854\times 10^{-12}}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B9%5Ctimes%2010%5E%7B-6%7D%7D%7B2%5Ctimes%208.854%5Ctimes%2010%5E%7B-12%7D%7D)
E = 5.08 x 10^5 N/C
Answer:
Maximum height of rocket = 2538.74 m
Explanation:
We have equation of motion s = ut + 0.5 at²
For first 5 seconds
s = 0 x 5 + 0.5 x 40 x 5² = 500 m
Now let us find out time after 5 seconds rocket move upward.
We have the equation of motion v = u + at
After 5 seconds velocity of rocket
v = 0 + 40 x 5 = 200 m/s
After 5 seconds the velocity reduces 9.8m/s per second due to gravity.
Time of flying after 5 seconds
![t=\frac{200}{9.81}=20.38s](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B200%7D%7B9.81%7D%3D20.38s)
Distance traveled in this 20.38 s
s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m
Maximum height of rocket = 500 +2038.74 = 2538.74 m
Answer:
Energy stored in the capacitor will be ![1.835\times 10^{-6}J](https://tex.z-dn.net/?f=1.835%5Ctimes%2010%5E%7B-6%7DJ)
Explanation:
We have given edge length of capacitor = ![1.2\times 10^2cm=1.2m](https://tex.z-dn.net/?f=1.2%5Ctimes%2010%5E2cm%3D1.2m)
So area A = 1.2×1.2 = 1.44 ![m^2](https://tex.z-dn.net/?f=m%5E2)
Separation is given as d 1 mm = ![10^{-3}m](https://tex.z-dn.net/?f=10%5E%7B-3%7Dm)
We know that capacitance is given by ![C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 1.44}{10^{-3}}=12.744\times 10^{-9}F](https://tex.z-dn.net/?f=C%3D%5Cfrac%7B%5Cepsilon%20_0A%7D%7Bd%7D%3D%5Cfrac%7B8.85%5Ctimes%2010%5E%7B-12%7D%5Ctimes%201.44%7D%7B10%5E%7B-3%7D%7D%3D12.744%5Ctimes%2010%5E%7B-9%7DF)
Voltage is given as V = 12 volt
We know that energy stored is given by ![E=\frac{1}{2}CV^2=\frac{1}{2}\times 12.744\times 10^{-9}\times 12^2=1.835\times 10^{-6}J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7DCV%5E2%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2012.744%5Ctimes%2010%5E%7B-9%7D%5Ctimes%2012%5E2%3D1.835%5Ctimes%2010%5E%7B-6%7DJ)
Answer: V = 504m/a
F = 4N
Explanation: please find the attached file for the solution