Answer:
The velocity of the train is 82.8 km/h
Explanation:
The equation for the position of the train and the car is as follows:
x = x0 + v · t
Where:
x = position at time "t".
x0 = initial position.
v = velocity.
t = time.
First, let´s calculate the distance traveled by the car in 60 s (1/60 h). Let´s place the origin of the frame of reference at the front of the train when it starts to pass the car so that the initial position of the car is 0 (x0 = 0 m):
x = 0 m + 72 km/h · (1/60) h
x = 1.2 km.
Then, if the whole train passes the car at that time, the position of the front of the train at that time will be 1.2 km + 0.18 km = 1.38 km.
Then using the equation of position we can obtain the velocity:
x = x0 + v · t
1.38 km = 0 m + v · (1/60) h
1.38 km / (1/60) h = v
v = 82.8 km/h
The velocity of the train is 82,8 km/h
The same result could be obtained using the rear of the train. You only have to identify where the rear is at t = 0 and where it is at t = 60 s.
Try it!
Answer:
Explanation:
Since X-rays are high (energy) frequency photons and radio waves are composed of low (energy) frequency photons, X-rays are more energetic and can do more harm to organic materials (such as cells).
Answer:
s₁ = 0.022 m
Explanation:
From the law of conservation of momentum:
where,
m₁ = mass of hockey player = 97 kg
m₂ = mass of puck = 0.15 kg
u₁ = u₂ = initial velocities of puck and player = 0 m/s
v₁ = velocity of player after collision = ?
v₂ = velocity of puck after hitting = 48 m/s
Therefore,
negative sign here shows the opposite direction.
Now, we calculate the time taken by puck to move 14.5 m:
Now, the distance covered by the player in this time will be:
<u>s₁ = 0.022 m</u>
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Answer:
Explanation:
given,
initial velocity of the ball = 20 m/s
angle of ramp = 22°
ball travel at a distance = 5 m
a) for friction less
v = 17.58 m/s
b) considering the friction
v = 17.16 m/s
