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3 years ago

13

calculate the work done by 2N force directed at 30 degree to the vertical to move a 500g box a horizontal distance of 400 cm acr

oss a rough floor at constant speed of 0.5 m per second

1 answer:

sattari [20]3 years ago

3 0

Answer:

there is no picture :o?

Explanation:

:oo

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Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

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$Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}$

$GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} } \approx 1.42\cdot 10^{12}m$

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3 years ago

In the lab, you submerge 100 g of 40°C nails in 200 g of 20°C water. (The specific heat of iron is 0.12 cal/g # °C.) Equate the

Deffense [45]

Answer:

Final temperature of the mixture becomes

$T = 21.13^oC$

Explanation:

Here we know that heat given by the nail is equal to the heat absorbed by water

So here we know that heat to change the temperature is given as

$Q = ms\Delta T$

so by equating the heat we have

$m_{iron}s_{iron}\Delta T = m_{water}s_{water}\Delta T$

now we have

$100 (0.12) (40 - T) = 200 (1) (T - 20)$

$4.8 - 0.12 T = 2T - 40$

$44.8 = 2.12 T$

$T = 21.13^oC$

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