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8090 [49]
3 years ago
13

calculate the work done by 2N force directed at 30 degree to the vertical to move a 500g box a horizontal distance of 400 cm acr

oss a rough floor at constant speed of 0.5 m per second​
Physics
1 answer:
sattari [20]3 years ago
3 0

Answer:

there is no picture :o?

Explanation:

:oo

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At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant
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(a) We must first look at the formulas of the velocities of each toy car. v1 =
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(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

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