Answer:
108.37°C
Explanation:
P₁ = Initial pressure = 101 kPa
V₁ = Initial volume = 530 m³
T₁ = Initial temperature = 10°C = 10+273.15 =283.15 K
P₂ = Final pressure = 101 kPa (because it is open to atmosphere)
V₂ = Final volume = 530 m³
P₁V₁ = n₁RT₁
⇒101×530 = n₁RT₁
⇒53530 J = n₁RT₁
P₂V₂ = n₂RT₂
⇒53530 J = n₂RT₂
Dividing the first two equations we get
∴Temperature must the air in the balloon be warmed before the balloon will lift off is 381.25-273.15 = 108.37°C
Why does a satellite in a circular orbit travel at a constant speed? why does a satellite in a circular orbit travel at a constant speed? there is a force acting opposite to the direction of the motion of the satellite. there is no component of force acting along the direction of motion of the satellite. the net force acting on the satellite is zero. the gravitational force acting on the satellite is balanced by the centrifugal force acting on the satellite?
..b.25
Answer:
20m/s²
Explanation:
force = mass*acceleration
acceleration = force ÷ mass
acceleration = 200N ÷ 10kg
acceleration = 20m/s²
The bigger the object the greater the gravitational pull, so the farther away the big object is its gravitational force begins to decrease. Refer to the picture for more explanation.
