The given condition for a 100% efficient step down transformer is not true.
<h3>
How do Step-down Transformers work?</h3>
Because there are fewer turns in the secondary winding of a step-down transformer, the secondary voltage is lower than the initial voltage. As a result, this kind of transformer is employed to reduce the voltage to the levels intended for the circuit. Almost all power supply incorporate a step-down transformer to keep the operating voltage range of the circuit within acceptable limits. Electronic transformers and distribution systems are often where these transformers are installed (power transformers).
<h3>
What Does a Step-Down Transformer Mean by Power?</h3>
Using the system voltage and current, we can calculate the power of a transformer. Volt-Amps, or VA, is the unit used to measure the power in a transformer (for larger transformers Kilo Volt-Amps, kVA).
Any transformer should, in theory, have constant power on both sides, which implies that the power available on the secondary side of the transformer should match the power available on the primary side. This also applies to step-down transformers. A step-down transformer's secondary side has a lower voltage than its primary side, hence in order to balance the transformer's total power, the secondary current would need to be increased.
<h3>
What is the Step-Down Transformer's Relationship Between Voltage and Current?</h3>
In a step-down transformer, the output current is greater than the input current while the output voltage is lower than the primary voltage.
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Answer:
The soup still is cool, or since its recent it will take a while to get warmer
Explanation:
Answer:
Explanation:
Given
Velocity = 388m/s
Height S = 2.89m
Required
Time
Using the equation of motion
S =ut+1/2gt²
2.89 = 388t+1/2(9.8)t²
2.89 = 388t+4.9t²
Rearrange
4.9t²+388t-2.89 =0
Factorize
t = -388±√388²-4(4.9)(2.89)/2(4.9)
t= -388±√(388²-56.644)/9.8
t = -388±387.93/9.8
t =0.073/9.8
t = 0.00744 seconds
Explanation:
thet amplify DC, because of the voltage ( small current input signal)
Answer:
The normal force the seat exerted on the driver is 125 N.
Explanation:
Given;
mass of the car, m = 2000 kg
speed of the car, u = 100 km/h = 27.78 m/s
radius of curvature of the hill, r = 100 m
mass of the driver, = 60 kg
The centripetal force of the driver at top of the hill is given as;

where;
Fc is the centripetal force
is downward force due to weight of the driver
is upward or normal force on the drive

Therefore, the normal force the seat exerted on the driver is 125 N.