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Arlecino [84]
2 years ago
11

What is the potential difference across lamp 1

Physics
1 answer:
Alex73 [517]2 years ago
7 0

Answer:

1+1=2

Explanation:

You just need to add and voila the answer

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Doe anyone get this ​
8_murik_8 [283]

Answer:

we know a = F/ M

Explanation:

  • 2 m/s²
  • 0.19 m/s²
  • 9.25 m/ s²
  • 0.04 m/s²
  • 100.39 m/s²

4 0
3 years ago
Strip electrons from an atom and the atom becomes a
Dafna11 [192]
It becomes a positive Iron
7 0
3 years ago
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A classroom that normally contains 40 people is to be airconditioned with window air-conditioning units of 5-kW cooling capacity
oksano4ka [1.4K]

Answer:

About  2 units.

Explanation:

We assume that there is no heat dissipating instrument in the room

Total cooling load of the room is defined from the given below equation

Q_{cooling}=Q_{light}+Q_{people}+Q_{heat gain}

where

Q_{light}= 10*100 W =1 KW

Q_{people} = 40*360 KJ/h= 4 KW

Q_{heat gain}=15000KJ/h= 4.17 KW

Q_{cooling}= 1+4+4.17=9.17 KW

the number of air conditioner unit is =\frac{9.17}{5}=1.83

 which is approximately 2 units

   

7 0
3 years ago
which has a greater speed, a heron that travels 600 m in 60 seconds or a duck that travels 60 m in 5 seconds
nasty-shy [4]
A duck has a greater speed
8 0
3 years ago
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While standing on a bridge 15 m above the ground, you drop a stone from rest. When the stone has fallen 3.2 m, you throw a secon
AURORKA [14]

Answer:

11.3 m/s

Explanation:

First, find the time it takes for the first stone to fall 3.2 m.

Given:

Δy = 3.2 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(3.2 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.81 s

Next, find the time for the first stone to land.

Given:

Δy = 15 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(15 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.75 s

The difference in time is 1.75 s − 0.81 s = 0.94 s.  Find the initial velocity needed for the second stone to land after that amount of time.

Given:

Δy = 15 m

a = 9.8 m/s²

t = 0.94 s

Find: v₀

Δy = v₀ t + ½ at²

(15 m) = v₀ (0.94 s) + ½ (9.8 m/s²) (0.94 s)²

v₀ = 11.3 m/s

5 0
3 years ago
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