Well first of all, since the question deals with the relationship of Charon and Pluto, we don't care about their distance from the sun, because that has no effect on the gravitational forces between them.
All we need is Newton's law of universal gravitation:
Gravitational forces = G m₁ m₂ / D² .
' G ' is the gravitational constant ... 6.67 x 10⁻¹¹ newt-m²/kg²
m₁ = either one of the masses ... 1.31 x 10²² kg (Pluto)
m₂ = the other mass ... 1.55 x 10²¹ kg (Charon)
D = the distance between their centers ... 1.96 x 10⁷ meters
Gravitational forces = G m₁ m₂ / D²
= (6.67 x 10⁻¹¹ newt-m²/kg²)
times (1.31 x 10²² kg) times (1.55 x 10²¹ kg)
divided by (1.96 x 10⁷ meters)²
= (6.67 x 1.31 x 1.55 x 10⁻¹¹ ⁺ ²² ⁺ ²¹ ⁻ ¹⁴) / (1.96)²
= (13.54 x 10¹⁸) / (3.84) = 3.53 x 10¹⁸ newtons .
<span>This is the gravitational force of attraction that Pluto exerts
on Charon. It's also the </span><span>gravitational force of attraction that
Charon exerts on Pluto. The gravitational forces are always
equal and opposite.
</span>
Answer:
1. The proton is deflected toward the east by the magnetic force, but its kinetic energy does not change
Explanation:
This is consequently because the magnetic field unlike the electric field, deflects the electron but does not change its speed or kinetic energy.
When air resistance is equal to the sack's weight, it will no longer accelerate (so its acceleration will be zero) and will be falling at terminal velocity.
Answer:
5 meters per second squared
Explanation:
We calculate the acceleration using the formula:
a = (vf - vi) / t
where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.
In our case:
a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2
Answer:
Explanation:
Capacity of a parallel plate capacitor C = ε₀ A/ d
ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.
C =( 8.85 X10⁻¹² X 27 X 10⁻⁴ ) / 3 X 10⁻³
= 79.65 X 10⁻¹³ F.
potential diff between plate = Charge / capacity
= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³
= 601 V
Electric field = V/d
= 601 / 3 x 10⁻³
= 2 x 10⁵ N/C
Force on proton
= charge x electric field
1.6 x 10⁻¹⁹ x 2 x 10⁵
= 3.2 x 10⁻¹⁴
Acceleration a = force / mass
= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷
= 1.9 x 10¹³ m s⁻²
Distance travelled by proton = 3 x 10⁻³
3 x 10⁻³ = 1/2 a t²
t = 
t = 1.77 x 10⁻⁸ s
