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mash [69]
3 years ago
10

A ball thrown across a football field is an example of a(n)

Chemistry
1 answer:
Cloud [144]3 years ago
7 0

I don't know what you mean by the question, but in science it is Newton's second law.

"The second law explains how the velocity of an object changes when it is subjected to an external force."

I hope this helped!+*♡

You might be interested in
explain how a metal with one valence electron compares with a metal with more than one valence electron
slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

  • Metals generally have large sizes.
  • when the electron in this shell is lost, the metal atom can then attain stability.
  • therefore, such atom will quickly want to combine with any other willing to accept the electron so that they can be stable.
  • Those with more than one electron will find it difficult to lose them.
  • It requires huge energy to remove such electrons compared to the ones with only one valence electron.

learn more:

Valence electrons brainly.com/question/3023499

#learnwithBrainly

7 0
3 years ago
What type of bond would form between two atoms of selenium? A. Double ionic bond B. Single ionic bond C. Single covalent bond D.
kirill115 [55]

The corret answer is D

3 0
3 years ago
An element has three different isotopes. One has a mass of 35.00 amu; another has a mass of 36.00 amu; and another has a mass of
yulyashka [42]

Answer:

so 35+38+36÷3= 109÷3 =36.33 AMU

8 0
3 years ago
For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [
sveta [45]

Explanation:

The given data is as follows.

     E^{o} = 0.483,     [Co^{3+}] = 0.173 M,

     [Co^{2+}] = 0.433 M,     [Cl^{-}] = 0.306 M,

     P_{Cl_{2}} = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P = \frac{n}{V}RT    

Also, we know that

                Density = \frac{mass}{volume}

So,         P = MRT

and,          M = \frac{P}{RT}

                    = \frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}

                    = \frac{9.0}{24.436}

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E = E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}

             = 0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}

             = 0.483 - 0.02955 log \frac{0.0689}{0.0162}

             = 0.483 - 0.02955 \times 0.628

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at 25^{o}C is 0.4645 V.

4 0
4 years ago
Are pure substances homogeneous or heterogeneous
Svetllana [295]

The answer is homogenous i think

6 0
3 years ago
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