a pro golfer hits 45.0-gram golf ball, giving its speed of 75.0 m/s. what is the momenntum has the golfer given to the ball

Chemistry

1 answer:

AfilCa [17]2 years ago

6 0

Momentum = mass x velocity. 45g = 0.045kg. 0.045 x 75 = 3.375 kgm/s

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Answer:

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Explanation:

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if 5430 J of energy is used to heat 1.25 L of room temp. water (23.0 °C) whats the final temp of the water?

skelet666 [1.2K]

We can use the heat equation,
Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

Density = mass / volume

The density of water = 0.997 g/mL

Hence mass of 1.25 L (1250 mL) of water = 0.997 g/mL x 1250 mL

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Specific heat capacity of water = 4.186 J/ g °C.

Let's assume that there is no heat loss to the surrounding and the final temperature is T.

By applying the equation,

5430 J = 1246.25 g x 4.186 J/ g °C x (T - 23) °C
(T - 23) °C = 5430 J / 1246.25 g x 4.186 J/ g °C
(T - 23) °C = 1.04 °C
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3 years ago

How many electrons, protons, and neutrons does Lithium have?

Andrej [43]

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3 years ago

The gas in a cylinder has a volume of 3 liters at a pressure of 118 kpa. the pressure of the gas is increased to 221 kpa. assumi

Soloha48 [4]

Data:
V1 (initial volume) = 3 g/L
P1 (initial pressure) = 118 kPa
V2 (final volume) = ? (g/L)
P2 (final pressure) = 221 kPa

Formula:
P1 * V1 = P2 * V2

Solving:
P1 * V1 = P2 * V2
118 * 3 = 221 * V2
354 = 221 V2
221 V2 = 354
$V_{2} = \frac{354}{221}$
$\boxed{\boxed{V_{2} \approx 1.60\:g/L}}\end{array}}\qquad\quad\checkmark$

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Mumz [18]

Answer:

substance*? a particular kind of matter with uniform properties.

Explanation:

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2 years ago