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andrew-mc [135]
3 years ago
10

According to Newton's law of universal gravitation, which of these objects would have the strongest gravitational force?

Physics
1 answer:
bixtya [17]3 years ago
4 0
A golf ball less resistance-smaller object
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A 2kg Book is sitting on a table.a 10n Force is pulling to the right.a 3n Force is pulling to the left what is the net force act
salantis [7]


The net force = sum of all forces acting on the body



If we take left side as -ve and right side as +ve,
then,

The net force here would be equal to,
10N + (- 3N)
= 7N.


Therefore, a net force of +7N ( + indicates it's moving towards right) is acting on the book of mass 2kg.


4 0
3 years ago
Hey Jatin .
snow_tiger [21]

Answer:

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6 0
3 years ago
A.
Elanso [62]

Answer:

Well, their are two answers in their. It would be Ask their Parent for assistance in persuading and Ask for an opportunity to earn extra credit:)

Explanation:

3 0
3 years ago
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A ski jumper travels down a slope and
AleksandrR [38]

Answer:

304.86 metres

Explanation:

The x and y cordinates are dcos\theta and dsin\theta respectively

The horizontal distance travelled, x=v_{ox}t=dcos\theta

Making t the subject, t=\frac{dcos\theta}{v_{ox}}

Since y=0.5gt^2=dsin\theta, we substitute t with the above and obtain

0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta

Making d the subject we obtain

d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}

d=\frac{2*30^2sin48}{9.8cos^248}

d=304.8584

d=304.86m

5 0
3 years ago
A solid sphere of mass 4.0 kg and radius 0.12 m starts from rest at the top of a ramp inclined 15°, and rolls to the bottom. The
cluponka [151]

Answer:

v = 4.1 m/s

Explanation:

As per mechanical energy conservation law we can say that initial total gravitational potential energy of the sphere is equal to final kinetic energy of rolling

so we will say

mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2

now for pure rolling condition we know that

v = R\omega

so we will have

mgh = \frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mR^2)(\frac{v^2}{R^2})

mgh = \frac{7}{10}mv^2

now we will have

v^2 = \sqrt{\frac{10}{7}gh}

v^2 = \sqrt{\frac{10}{7}(9.8)(1.2)}

v = 4.1 m/s

7 0
3 years ago
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