Recall this kinematic equation:
a =
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a =
Answer:
33 kg m/s
Explanation:
The momentum of an object is given by:
where
m is the mass of the object
v is the velocity of the object
In this problem, the total mass of the child and the wagon is m =22 kg, while the velocity is v = 1.5 m/s, therefore the momentum is
To solve this problem it is necessary to apply the concepts related to the conservation of angular momentum. This can be expressed mathematically as a function of inertia and angular velocity, that is:
Where,
I = Moment of Inertia
= Angular Velocity
For the given object the moment of inertia is equivalent to
Considering that the moment of inertia varies according to distance, and that there are two of these without altering the mass we will finally have to
Our values are given as,
Replacing we have,
Therefore the angular speed after the catch slips is 0.2rad/s