It can be said that most of the required information's are already given in the question.
Let us assume the speed of the passenger train = x
Speed of the freight train = y
x = y + 40
The second equation will be
6 * x = 10 * y
6x = 10y
Dividing both sides by 2, we get
3x = 5y
x = 5y/3
Putting the value of "x" in the first equation, we get
x = y + 40
5y/3 = y + 40
5y = 3y + 120
5y - 3y = 120
2y = 120
y = 60 mph
Putting the value of y in the first equation, we get
x = y + 40
= 60 + 40
= 100 mph
From the above deduction, we can conclude that the passenger train is traveling at 100 mph and the freight train is traveling at 60 mph.
Answer:
Explanation:
The torque is the force by the distance so to determinate that both torque are the same magnitude so
Solve to d2
Scientists can tell this by looking at seismic waves released by earthquakes. ( if you need me to elaborate more ask)
The amount left of a radioactive sample amount N0 if the decay constant is 0.00125 seconds and the time is 180 seconds is 0.7999 N.
<h3>What is half-life?</h3>
The time it takes for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life T1/2 and the decay constant is given by T1/2 = 0.693/λ.
- N=N0e−λt
- given λ = 0.00125 seconds
- t = 180 seconds
- Now putting values.
- N=N0e−λt = 0.799
- N= 0.7999.
Read more about the radioactive :
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Answer:
188 A
Explanation:
Parameters given:
Length of cable, L = 0.78 m
Angle, θ = 60º
Magnetic field, B = 5.5 * 10^(-5) T
Force experienced by wire, F = 7 * 10^(-3) N
The force experienced by a current carrying wire of length L, due to a magnetic field B is given as:
F = I * L * B * sinθ
=> I = F/(L * B * sinθ)
I = (7 * 10^(-3)) / (0.78 * 5.5 * 10^(-5) * sin60)
I = 188 A
