Answer:
19.09 m/s
Explanation:
u = 0, h = 18.6 m
Use third equation of motion
v^2 = u^2 + 2 g h
v^2 = 0 + 2 x 9.8 x 18.6
v = 19.09 m/s
Answer:
-0.10472
Explanation:
Remember that any <u><em>clockwise</em></u> rotation is considered negative, and any <u><em>counterclockwise</em></u> rotation is considered positive.
The formula for period is:

Solve for
and you get:

The period is 60 seconds so make that division and you're left with -0.10472
or -0.10
if significant figures apply (negative because the rotation is clockwise).
Answer:
a) The astronauts would see the real length of the meter stick, i.e. L₀
b) The length of the meter stick as measured by the stationary observer will be 
Explanation:
a) Let the proper length of the meter stick be L₀
The meter stick and the astronauts on the on the space ship are on the same moving frame, therefore, they will see the exact length of the meter stick, that is, L₀
b) A stationary observer watching the space ship and meter stick travel past them will see a contracted length of the meter stick
The original length = L₀
Let the speed of the space ship = v
The contracted length, L, is related to the original length in the frame of rest by
L = L₀/γ......................(1)
Where γ =
....................(2)
Substituting equation (2) into (1)

The heat remains constant because there’s nothing to cool it down