Answer:
a) P =392.4[Pa]; b) F = 706.32[N]
Explanation:
With the input data of the problem we can calculate the area of the tank base
L = length = 10[m]
W = width = 18[cm] = 0.18[m]
A = W * L = 0.18*10
A = 1.8[m^2]
a)
Pressure can be calculated by knowing the density of the water and the height of the water column within the tank which is equal to h:
P = density * g *h
where:
density = 1000[kg/m^3]
g = gravity = 9.81[m/s^2]
h = heigth = 4[cm] = 0.04[m]
P = 1000*9.81*0.04
P = 392.4[Pa]
The force can be easily calculated knowing the relationship between pressure and force:
P = F/A
F = P*A
F = 392.4*1.8
F = 706.32[N]
Answer:
Approximately 
, assuming that 
.
Explanation:
Let 
denote the time required for the package to reach the ground. Let 
and 
denote the initial and final height of this package.
.
For this package:
- Initial height:
. - Final height:
(the package would be on the ground.)
Solve for , the time required for the package to reach the ground after being released.
.
.
Assume that the air resistance on this package is negligible. The horizontal ("forward") velocity of this package would be constant (supposedly at 
.) From calculations above, the package would travel forward at that speed for about 
. That corresponds to approximately:
.
Hence, the package would land approximately in front of where the plane released the package.
Multiply the power (1,800 watts) by time (1,200 seconds) to get 2,160,000 joules (or 2.16 MJ)
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