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Sergeu [11.5K]
3 years ago
15

Alka-seltzer is an antacid that is dissolved in water before use. for an experiment, three tablets of alka-seltzer are dissolved

in three beakers, each containing 50 ml of water: beaker a's water is 10° c; beaker b's water is 50° c; and beaker c's water is 80°
c. which answer correctly orders the reaction rates of the three beakers from fastest to slowest reaction? beaker a > beaker b > beaker c beaker c > beaker b > beaker a beaker b > beaker a > beaker c beaker a = beaker b = beaker c
Chemistry
1 answer:
Naddika [18.5K]3 years ago
8 0

Alka-seltzer in an antacid that contains a mixture of sodium bicarbonate and citric acid. When the tablet is dissolved in water, the reactants which are in solid form in tablet become aqueous and react with each other.

During this reaction, Carbon Dioxide gas is evolved which causes the reaction mixture to fizz. The equation is given below.

NaHCO_{3}\ (aq) +  H_{3}C_{6}H_{5}O_{7} (aq)\rightarrow Na_{3}C_{6}H_{5}O_{7}(aq)+ CO_{2}(g)+H_{2}O (l)

Rate of the above reaction is affected by the Temperature.

As the temperature increases , the rate of the reaction increases. This happens because at higher temperature, the collisions between reacting species are more which result in formation of product in less time. This increases the rate of reaction.

We have been given equal volumes of water for each beaker. But the temperature of beaker c is 80°C which is the highest temperature. That means the reaction in beaker c is fastest.

Whereas beaker a is at lowest temperature (30°C) , therefore the reaction in beaker a would be slowest .

Therefore the answer that correctly orders the reaction rates from fastest to slowest reaction is beaker c > beaker b > beaker a

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4 0
3 years ago
Pure chlorobenzene (C6H5Cl) has a normal boiling point of 131.00 °C. A solution of 32.5 g of 2,8-dibromodibenzofuran (C12H6Br2O)
vichka [17]

Answer:

Kb →  1.56 °C / m

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This is all about boiling point elevation, the colligative property that shows that boiling point for a solution is higher than boiling point of pure solvent.

This is the formula: ΔT = Kb . m . i

where i is the Van't Hoff factor (ions dissolved in solution). As these are organic compounds, we assume they are non electrolytic,

m is molality (mol of solute / 1kg of solvent)

Kb is our unknown. The value for ebulloscopic constant, it is specific for each solvent.

ΔT = T° boiling from solution - T° boiling from solute

First of all, let's determine the moles of solute.

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We must convert the mass from g to kg

195g . 1kg /1000 = 0.195 kg

Molality = 0.286 mol / 0.195 kg = 1.47 m

Let's replace the values in the formula

133.30 °C - 131°C = Kb . 1.47m .1

2.30°C / 1.47 m =  Kb →  1.56 °C / m

3 0
3 years ago
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