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zubka84 [21]
3 years ago
9

Root nodules are associations between bacteria and plant roots responsible for

Chemistry
1 answer:
max2010maxim [7]3 years ago
8 0

Answer: Root nodules are associations between bacteria and plant roots responsible for nitrogen fixation.

Explanation:

  • As nitrogen present in atmosphere cannot be used by plants directly.
  • Nitrogen present in atmosphere is converted into nitrogen compounds by bacteria which is present in root nodules of a plant.
  • These compounds of nitrogen are then used by plants for various functions.
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Which of the following is a characteristic of mixtures? A. Mixtures can only be in solid and liquid form. B. Substances that are
Taya2010 [7]

The correct choice is B.  

Mixtures retain their properties because science has proven it. Take a bag of trail mix for example. Those raisins and marshmallows and m&m’s can each be separated. When you take them out, they keep their same texture.  

 

Is not correct because mixtures can be solids (Trail mix is one example)  

Correct  

Is not correct because sometimes it cannot be seen (Lemonade powder and water is one example)  

Is not correct because trail mix is an example.

5 0
3 years ago
The volume of 7.91 M HCl needed to make 196.1 mL of 2.13 M HCl is ____.
Alona [7]

Answer:

a. 52.8

Explanation:

To find the number of moles of HCl we use the relation M₁V₁=M₂V₂

where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.

M₁=7.91 M

M₂=2.13 M

V₁=?

V₂=196.1 mL

Replacing these values in the relationship.

M₁V₁=M₂V₂

7.91 M× V₁=2.13 M×196.1 mL

V₁=(2.13 M×196.1 mL)/7.91 M

=52.8 mL

3 0
3 years ago
This is the chemical formula for zinc bromate: . Calculate the mass percent of oxygen in zinc bromate. Round your answer to the
Paladinen [302]

Answer:

30%

Explanation:

<em>This is the chemical formula for zinc bromate: Zn(BrO₃)₂. Calculate the mass percent of oxygen in zinc bromate. Round your answer to the nearest percentage.</em>

Step 1: Determine the mass of 1 mole of Zn(BrO₃)₂

M(Zn(BrO₃)₂) = 1 × M(Zn) + 2 × M(Br) + 6 × M(O)

M(Zn(BrO₃)₂) = 1 × 65.38 g/mol + 2 × 79.90 g/mol + 6 × 16.00 g/mol

M(Zn(BrO₃)₂) = 321.18 g/mol

Step 2: Determine the mass of oxygen in 1 mole of Zn(BrO₃)₂

There are 6 moles of atoms of oxygen in 1 mole of Zn(BrO₃)₂.

6 × m(O) = 6 × 16.00 g = 96.00 g

Step 3: Calculate the mass percent of oxygen in Zn(BrO₃)₂

%O = mO/mZn(BrO₃)₂ × 100%

%O = 96.00 g/321.18 g × 100% ≈ 30%

3 0
3 years ago
ΔH for the formation of CuCl2 from its elements is -220.1 kJ/mol. How many kJ are associated with the formation of 0.30 mole of
otez555 [7]
0.3 * - 220.1 = - 66.03kJ
3 0
3 years ago
Read 2 more answers
What is the ph of a 0.034 m hydrochloric acid solution?
Law Incorporation [45]
PH= -log [H+]   
= - (log 0.034)   
= - (-1.5)   
= 1.5
8 0
3 years ago
Read 2 more answers
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