Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
Answer:
3 hours
Step-by-step explanation:
4.5*(2/3)
= 3 hours
Answer:
the equation of the line is 7x + y = 0 .
Step-by-step explanation:
in the standard form of the line that is Ax +By = C we can write it in the form of
By = C - Ax
which is in the form of 
where m is the slope of the line and c is y intercept made by the line.
comparing and
we get that 
and 
since it is given that slope of the line is -7 therefore m = -7 and c = 0
therefore 
and 
therefore C = 0 , A = 7 and B = 1
therefore the equation becomes 7x + y = 0
Answer:
f(1) = 2
Step-by-step explanation:
Since y is a function of x, that is;
y = f(x)
f(1) implies the value of y when x = 1.
To obtain this value we draw the vertical line x = 1 and check where the line intersects the graph of f(x).
In this case, the line x = 1 will intersect with the graph of f(x) on the line y = 2. The function f(x) assumes the value 2 between x = 0 and x = 4. Therefore,
f(1) = 2
Answer:
(a) Co-ordinate rule is 
and 
(b) Co-ordinates of B' and C' are 
and 
respectively.
Step-by-step explanation:
(a)
Here, the co-ordinates of A
are translated to A'
.
For the co-ordinates A and A', 
and 
So, x value of A has shifted to right by 6 units and y value of A has shifted 8 units down.
Hence, the co-ordinate rule that maps ΔABC onto ΔA'B'C' is:
and .
(b)
Using the co-ordinate rule, we can find the co-ordinates of B' and C'.
For B, 
and 
.
So, 
of B' is 
And, 
of B' is 
.
Therefore, co-ordinates of B' are .
For C, 
and 
.
So, of C' is 
And, of C' is 
.
Therefore, co-ordinates of C' are .
