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jenyasd209 [6]
4 years ago
5

What system of units do scientist use to measure the properties of matter

Physics
2 answers:
dezoksy [38]4 years ago
7 0
 Gram (g) is a metric unit used to measure the mass of small objects.Kilogram (kg) is equal to 1,000 grams, so it is used to measure the mass of larger objects. 
valentinak56 [21]4 years ago
3 0
<span>weight = (mass) * (force of gravity)  or w=mg.</span>
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A uniform rod is set up so that it can rotate about a perpendicular axis at one of its ends. The length and mass of the rod are
igor_vitrenko [27]

Answer:

0.231 N

Explanation:

To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

\alpha = \frac{\theta}{t} = \frac{6.37}{9.87} = 0.6454 rad/s^2

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

I = \frac{mL^2}{3} = \frac{1.27*0.847^2}{3} = 0.303kgm^2

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

T = I\alpha = 0.303*0.6454 = 0.196 Nm

So the force acting on the other end to generate this torque mush be:

F = \frac{T}{L} = \frac{0.196}{0.847} = 0.231 N

4 0
4 years ago
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Anton [14]
Here are your answers

6 0
3 years ago
A ___________ mutation occurs when a base in the DNA sequence is replaced by a different base.
77julia77 [94]

Answer:

Missense Mutation

Explanation:

The types if mutations include: Missense mutation. This type of mutation is a change in one DNA base pair that results in the substitution of one amino acid for another in the protein made by a gene. An insertion changes the number of DNA bases in a gene by adding a piece of DNA.

3 0
3 years ago
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A certain car is capable of accelerating at a uniform rate of 0.85 m/s^2. What is the magnitude of the car's displacement as it
gogolik [260]

Solution: 85.11 m

Given:

acceleration of the car, a= 0.85 m/s^{2}

initial velocity,u=83km/h=23.05 m/s

final velocity, v=94 km/h=26.11 m/s

we need to find the displacement (s) of the car.

we would use the equation of motion:

2as=v^{2}-u^{2}\\&#10;\Rightarrow s=\frac{v^{2}-u^{2}}{2a} \\&#10;\Rightarrow s=\frac{26.11^{2}-23.05^{2}}{2\times0.85}\\&#10;\Rightarrow s=85.11 m

hence, the displacement done by the car is = 85.11 m

7 0
3 years ago
A 0.03-kg bullet is fired with a horizontal velocity of 470 m/s and becomes embedded in block B which has a mass of 3 kg. After
Gala2k [10]

Answer with Explanation:

We are given that

Mass of bullet,m_1=0.03 kg

u_1=470 m/s

m_2=3 kg

\mu_k=0.2

m_3=30 kg

We have to find the velocity of the bullet and block B after the first impact and final velocity of the carrier.

According to law of conservation of momentum

m_1u_1=(m_1+m_2)v

0.03(470)=(0.03+3)v

v=\frac{0.03(470)}{(0.03+3)}=4.65 m/s

Hence, the velocity of the bullet and block B after the first impact=4.65 m/s

According to law of conservation of momentum

(m_1+m_2)v=(m_1+m_2+m_3)V

(0.03+3)\times 4.65=(0.03+3+30)V

V=\frac{(0.03+3)\times 4.65}{(0.03+3+30)}

V=0.43 m/s

3 0
4 years ago
Read 2 more answers
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