To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,
PV = nRT
If we are to retain constant the variable n and V.
The percent yield can therefore be solved through the following calculation,
n = (10.5 L)/(22.4 L) x 100%
Simplifying,
n = 46.875%
Answer: 48.87%
Answer:
See explanation and image attached
Explanation:
Yttrium has many isotopes, the lowest mass number of Yttrium is 89Y.
Recall that electron capture converts an electron into a proton and then into a neutron with a consequent emission of a neutrino (v).
In electron capture, the mass number of the daughter nucleus remains the same as that of the parent nucleus while the atomic number of the daughter nucleus is less than that of the parent by one unit.
Answer:
The sequence of an amino acid P is:
Glu-Gly-Lys-Ala-Ser-Phe-Lys-Gln-Val-Ile
Explanation:
Fragments obtained on hydrolysis of decapeptide P by the action of an enzyme named trypsin:
- Glu-Gly-Lys,
- Gln-Val-Ile
- Ala-Ser-Phe-Lys
Fragments obtained on hydrolysis of decapeptide P by the action of an enzyme named chymotrypsin:
- Lys-Gln-Val-Ile,
- Glu-Gly-Lys-Ala-Ser-Phe
In order to determine the sequence of protein P , we will arrange fragments in such a way so that common fragments or the common parts of fragments should come under each other.
On arranging these fragments :
Glu-Gly-Lys-Ala-Ser-Phe
Glu-Gly-Lys
Ala-Ser-Phe-Lys
Lys-Gln-Val-Ile
Gln-Val-Ile
The sequence of an amino acid P is:
Glu-Gly-Lys-Ala-Ser-Phe-Lys-Gln-Val-Ile
