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3 years ago

Patty climbs a tree. While sitting on a branch, she drops a leaf and an acorn at the same time. What would happen?

Physics

1 answer:

Paul [167]3 years ago

5 0

Answer:

Patty climbs a tree. While sitting on a branch, she drops a leaf and an acorn at the sametime. What would happen? __The leaf would fall slower than the acorn due to air resistance, butif no air was there, they would fall at the same time.

Explanation:

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What happens to the boiling point of water as you climb higher up a mountain?

Maksim231197 [3]

The higher the pressure, the higher boiling point of water. At lower the pressure, the boiling point of water comes down. So, the lower pressure inreases the boiling resulting more evaporation. As we go higher in altitude, the atmospheric pressure decreases. This results in decreasing the boiling point at higher altitude and increase in boiling of water. In fact, at the sea level ,the the sea water boils at 100 degree C where atmospheric pressre is normal. However , the boiling takes place at a lower temperature at the top of a mountain due to low pressure. In other words the boling is faster at the top of a mountain than that at its foot.

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3 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

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4 years ago

What style of art represents people or objects exactly as they appear in life?

frozen [14]

REALISM shows things as they REALLY look.

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3 years ago

Read 2 more answers

If the moon was closer to earth how long would it take to orbit the earth? It is only right before the Roche limit, it’s theoret

Alex_Xolod [135]

Answer:

it would probably be the same but if the moon is closer gravity would infect us humans

Explanation:

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3 years ago

If you drive through water, your brakes may become slippery and ineffective. To dry the brakes off, __________.

GenaCL600 [577]

Answer:

Explanation:

Water at normal temperature is a good lubricant and will hinder the brake from working properly when the road is wet. To dry the brakes off, apply brakes gently as you accelerate. This will generate some heat that will evaporate the water with the help of friction.

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4 years ago