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zhannawk [14.2K]
3 years ago
7

An apple is held completely submerged just below the surface of water in a container. The apple is then moved to a deeper point

in the water. Compared with the force needed to hold the apple just below the surface, what is the force needed to hold it at the deeper point?
Physics
1 answer:
Tresset [83]3 years ago
4 0

Answer:

Explanation:

When the apple is held submerged in water , it experiences a buoyant force due to which it floats in water . One has to apply downward force to keep it submerged. The lower the buoyant force , lower the force needed to submerge it in water.

When apple is held at much deeper point , it experience greater pressure due to column of water around it . So its size or its volume decreases . But its weight remains the same . Due to less volume , buoyant force also decreases ( buoyant force is equal to weight of displaced volume of water. )

Due to buoyant force becoming less , force needed on apple  in downward direction will also be less.

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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
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The time interval for which the proton remains in the field is -

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<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

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Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

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Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

To solve more questions on Force on charged particle, visit the link below-

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Answer:

220 ohms

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R = 110 / 0.25

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I hope I helped:)
6 0
3 years ago
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