Explanation:
I remember that notation! The expression

is the 1st law of thermodynamics and it refers to the heat supplied to the system dQ which is also a change in its internal energy dU. The first term is the <u>partial</u> derivative of the internal energy U with respect to temperature T while the volume V is kept constant, as denoted by the subscript V. The 2nd term is similar but this time, temperature is kept constant while its volume partial derivative is being taken.
Ah, memories!
The final atmospheric pressure is 
Explanation:
Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

where
p is the gas pressure
V is the volume
The equation can also be rewritten as

where in our problem we have:
is the initial pressure (the atmospheric pressure at sea level)
is the initial volume
is the final pressure
is the final volume
Solving the equation for p2, we find the final pressure:

Learn more about ideal gases:
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Answer: Option (b) is the correct answer.
Explanation:
Since, there is a negative charge present on the ball and a positive charge present on the rod. So, when the negatively charged metal ball will come in contact with the rod then positive charges from rod get conducted towards the metal ball.
Hence, the rod gets neutralized. But towards the metal ball there is a continuous supply of negative charges. Therefore, after the neutralization of positive charge from the rod there will be flow of negative charges from the metal ball towards the rod.
Thus, we can conclude that negative charge spread evenly on both ends.
Answer: C. The amount of work needed to charge the capacitor is UE, because when integrating the equation W = integral qdV with the correct limits yield the equation for the energy stored on a capacitor, UE = 1/2qV.
Explanation:
The claim about the amount of work that is needed to charge the capacitor and give evidence to support this claim is option C "The amount of work needed to charge the capacitor is UE, because when integrating the equation W = integral qdV with the correct limits yield the equation for the energy stored on a capacitor, UE = 1/2qV".
Option C is the correct answer because when we a capacitor is being charged, the amount of work that's being stored as a potential energy.
Answer:
No its not possible in that yes heat flow is due to temperature different but with time equilibrium in temperature is reached hence there is no temperature difference at both ends at this time