Explanation:
The range <em>R</em> of a projectile is given the equation
The maximum range is achieved when 
so our equation reduces to
We can solve for the initial velocity 
as follows:
or
To find the maximum altitude H reached by the missile, we can use the equation
At its maximum height H, 
so we can write
or
![\:\:\:\:\:\:= \dfrac{[(9.6×10^3\:\text{m/s})\sin{45°}]^2}{2(9.8\:\text{m/s}^2)}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%5C%3A%3D%20%5Cdfrac%7B%5B%289.6%C3%9710%5E3%5C%3A%5Ctext%7Bm%2Fs%7D%29%5Csin%7B45%C2%B0%7D%5D%5E2%7D%7B2%289.8%5C%3A%5Ctext%7Bm%2Fs%7D%5E2%29%7D)
Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate . this means that electromagnetic waves can travel not only through air and solid materials bit also through vacuum of space.
Answer:
a) 6636 km
b) 0.0154
Explanation:
The height above the earth at its furthest point is 368 km
The height above the earth at its closest point is 164 km
Radius of the Earth is 6370 km
The distance of the satellite from the center of the earth to the furthest point is 6370 + 368 km = 6738 km
The distance of the satellite from the center of the earth to the closest point is 6370 + 164 = 6534 km
If we add together the sum of the distance of the satellite from the furthest and its closest distance, it is equal to the 2 major semi axis.
Basically,
2a = R + r
a = (R + r) / 2
a = (6738 + 6534) / 2
a = 13272 / 2
a = 6636 km
Eccentricity, e = (a - r) / a
Eccentricity, e = (6636 - 6534) / 6636
Eccentricity, e = 102 / 6636
Eccentricity, e = 0.0154
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Answer:
Rs. 432*10^3 (In kilowatts per hour)
I hope it will be useful.
