Question

A potter’s wheel moves from rest to an angular speed of 0.40 rev/s in 37.5 s.

Answer 1

The angular acceleration of the potter's wheel is 0.067 rad/s².

The given parameters:

• Final angular speed, ωf = 0.4 rev/s
• Time of motion, t = 37.5 s

What is angular acceleration?

• Angular acceleration of an object is the rate of change of angular speed of the object.

The angular acceleration of the potter's wheel is calculated as follows;

$\alpha = \frac{\Delta \omega }{t} \\\\\alpha = (0.4\ rev/s \times \frac{2 \pi \ rad}{1 \ rev} ) \times \frac{1}{37.5 \ s} \\\\\alpha = 0.067 \ rad/s^2$

Thus, the angular acceleration of the potter's wheel is 0.067 rad/s².

Learn more about angular acceleration here: brainly.com/question/25129606