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Damm [24]
3 years ago
11

A large clump of ice is placed into a saucepan and heated to at least 1000C. Explain the changes that would take place by using

the following terms: physical change, states of matter, compound, solid, liquid, vapor and temperature change."
Chemistry
2 answers:
Mamont248 [21]3 years ago
7 0
By start heating the water so,
1- the physical changes to the water will begin by going through different states of matter such as solid, liquid and gas vapor. 

2- Water is a compound, not an element (H2o).

3- It will change according to the temperature change also:

a- At zero C° it is at a freezing temperature.

b- when it starts to be heated from 0C° to 100 c°, it starts to change from freezing to the liquid state. 

c- At 100C° the water starts to change from liquid to vapor state until it disappears. 

IgorLugansk [536]3 years ago
7 0

Explanation:

When a large clump of ice is heated in a sauce pan at about 1000 degree celsius then the ice will start to melt. As a result, the solid state of water which is ice will change into liquid state.

And when the liquid starts to boil as temperature reaches 100 degree celsius then liquid state will change into vapor state until it disappears.

Since there is only change in state so, it is a physical change. Thus, states of matter will change when there will be change in temperature.

Hence, state of compound H_{2}O will change along with change in temperature.

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DaniilM [7]

Answer:

The new volume is 5.913*10^4 L

Explanation:

Step 1: Write out the formula to be used:

Using general gas equation;

P1V1 / T1 =P2V2 /T2

V2 = P1V1T2 / P2T1

Step 2: write out the values given and convert to standard unit's where necessary

P1 = 0.995atm

P2 0.720atm

V1 = 5*10^4 L

T1 = 32°C = 32+ 273 = 305K

T2 = -12°C = -12 + 273 = 261K

Step 3: Equate your values and do the calculation:

V2 = 0.995 * 5*10^4 * 261 / 0.720 * 305

V2 = 1298.475 * 10^4 / 219.6

V2 = 5.913 * 10^4 L

So the new volume of the balloon is 5.913*10^4 L

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