Hello!
The
dissociation reaction of HNO₃ is the following:
HNO₃ → H⁺ + NO₃⁻This is a strong acid, so the concentration of HNO₃ would be the same as the concentration of H⁺. The formula for pH is the following:
![pH=-log([H_3O^{+}])=-log(0,75M)=0,12](https://tex.z-dn.net/?f=pH%3D-log%28%5BH_3O%5E%7B%2B%7D%5D%29%3D-log%280%2C75M%29%3D0%2C12)
So, the pH would be
0,12Have a nice day!
They define acids as proton donors, and bases as proton acceptors
If you were to have:
HNO3 + H2O -> H3O+. + NO3-
You can see that the nitric acid (HNO3) gave a hydrogen ion which has 1 proton, 0 neutrons and 0 electrons to the water so we just say that it gave a proton.
Now let's see a base
NH3 + H2O -> NH4+ + OH-
Now, you can see that the ammonia (NH3) gained a hydrogen ion (proton) from the water to become ammonium(NH4). which means it accepted a proton
That's basically it. Feel free to ask if you have any further questions
Answer: 67.1 moles of SO2
Explanation:
Since the equation is already balanced, you would just need to cancel out the O2 and multiple the 67.1 mol by the 1 mol of SO2 to get your answer.