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marta [7]
3 years ago
14

What is the ΔG given the following? ΔH = 20 kJ/mol T = 15°C ΔS = .101 kJ/molK

Chemistry
1 answer:
DedPeter [7]3 years ago
6 0
∆G = ∆H-T∆S
=20×10^3-(15+273)(.101×10^3)
=20000-(288)(101)
=20000-29088
=-9088 joule = -9.088 kj
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Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
4 years ago
Science plz help due soon 6th grade Major grade
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Answer:

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5 0
3 years ago
16. The concentration of a solution of potassium hydroxide is determined by titration with nitric
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Answer:

M_{base}=0.709M

Explanation:

Hello,

In this case, since the reaction between potassium hydroxide and nitric acid is:

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We can see a 1:1 mole ratio between the acid and base, therefore, for the titration analysis, we find the following equality at the equivalence point:

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That in terms of molarities and volumes is:

M_{acid}V_{acid}=M_{base}V_{base}

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M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} =\frac{0.498M*42.7mL}{30.0mL}\\ \\M_{base}=0.709M

Regards.

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3 years ago
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11111nata11111 [884]

Answer:

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How to calculate the percentage of a anhydrous salt
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