A 0.134-A current is charging a capacitor that has square plates 6.00 cm on each side. The plate separation is 4.00 mm. (a) Find
1 answer:
Answer:
a) 1.51Vm/s
b)Id=0.134A
Explanation:
(a) The time rate of change of electric flux between the plates can be computed by using:
where Ic is the current of the capacitor, e0 is the dielectric permittivity of vacuum and A is the area of the capacitor.
(b) The displacement current coincides with capacitor current:
Id = 0.134A
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