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Natalija [7]
4 years ago
3

Determine the coefficient of restitution e for a steel ball dropped from rest at a height h = 2.41 m above a heavy horizontal st

eel plate if the height of the second rebound is h2 = 0.82 m.
Physics
1 answer:
devlian [24]4 years ago
4 0

For such cases where frictional forces can be neglected,  and the object is dropped from rest onto a horizontal surface, coefficient of restitution is equivalent to:

e =  √(h/H)

where,

h = bounce height

H = drop height


so, using the formula we get:

e =  √(0.82/2.4)

Hence, e = 0.583 

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Suppose that the speed of an electron traveling 2.0 km/s is known to an accuracy of 1 part in 105 (i.e., within 0.0010%). What i
OverLord2011 [107]

Answer: 2.89(10)^{-3} m

Explanation:

The <u>Heisenberg uncertainty principle</u> postulates that the fact each particle has a wave associated with it, imposes restrictions on the ability to determine its position and speed at the same time.  

In other words:  

It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.

Mathematically this principle is written as:

\Delta x \geq \frac{h}{4 \pi m \Delta V} (1)

Where:

\Delta x is the uncertainty in the position of the electron

h=6.626(10)^{-34}J.s is the Planck constant

m=9.11(10)^{-31}kg is the mass of the electron

\Delta V is the uncertainty in the velocity of the electron.

If we know the accuracy of the velocity is 0.001\% of the velocity of the electron V=2 km/s=2000 m/s, then \Delta V is:

\Delta V=2000 m/s(0.001\%)

\Delta V=2000 m/s(\frac{0.001}{100})

\Delta V=2(10)^{-2} m/s (2)

Now, the least possible uncertainty in position \Delta x_{min} is:

\Delta x_{min}=\frac{h}{4 \pi m \Delta V} (3)

\Delta x_{min}=\frac{6.626(10)^{-34}J.s}{4 \pi (9.11(10)^{-31}kg) (2(10)^{-2} m/s)} (4)

Finally:

\Delta x_{min}=2.89(10)^{-3} m

5 0
3 years ago
The earth exerts a gravitational force on the moon. the moon exerts a gravitational force on the earth. how do the magnitudes of
Sonbull [250]
The forces are the same like the third law of Newton states.I think
3 0
4 years ago
Qué significa el “delay televisivo
RUDIKE [14]

Answer:

Respuesta. Explicación: Viene del inglés significa retraso, es un efecto de sonido que consiste en la multiplicación y retraso modulado de una señal sonora. Una vez procesada la señal se mezcla con la original.

Explanation:

3 0
3 years ago
Physics !!!!!!!!!!!!!!!!!
madreJ [45]

Answer:

1) v = -0.89 m/s

2) v = 36.5 m/s

Explanation:

1) Given

The mass of the boy, M = 45 Kg

The mass of the skateboard, m = 2 Kg

The initial velocity of the boy and skateboard is zero

According to the law of conservation of linear momentum

                              MV + mv = 0

                                           V = - mv/M

Substituting the given values in the above equation

                                          V = -2 x 20/ 45

                                             = -0.89 m/s

Hence, the velocity of the boy, v = -0.89 m/s

2) Given

The mass of the boy, M = 47 Kg

The mass of the skateboard, m = 8 Kg

The initial combined velocity of the boy and skateboard, u = 4.2 m/s

The boy jumped off from the skateboard with velocity, V = -1.3 m/s

According to the law of conservation of momentum,

                      MV + mv = (M + m)u

                                    v = [(M + m)u - MV] / m

Substituting the given values,

                                     v = [(47 + 8)4.2 - 47(-1.3)] / 8

                                        = 36.5 m/s

Hence, the velocity of the skateboard, v = 36.5 m/s

3 0
4 years ago
How much current would flow in a device powered by four 1.5 V batteries through a bulb that had a resistance of 51.0 ohms?
Serhud [2]

Answer:

0.12A

Explanation:

Total voltage produced by the batteries;

V = 1.5 × 4 = 6 v

Then the current that is flowing through the device

Current(I) = V/R

; I = 6/51

;Current = 0.12A

4 0
3 years ago
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