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3 years ago

Rest and Motion are the relative term. why? explain with example(please help me (╥﹏╥))

Physics

1 answer:

klemol [59]3 years ago

3 0

Explanation:

it depens on the subject and object. Let's example

you are driving a tesla car with your dog sitting on your side. You will say that the dog is at REST

but your friend, standing in sidewalk, seeing the same dog, will say that your dog is moving because it has MOTION from your car

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Moving company uses a machine to raise a 900 Newton refrigerator to the second floor of a building machine consists of a single

Juliette [100K]

Mechanical advantage of a machine is the ratio of the output force over the input force or M=Fo/Fi. Since M=1, Fi=Fo, or the input force is equal to the output force. This means that to raise the refrigerator that weighs 900 N, we need the same input force of 900 N, or Fo=Fi=900 N.

6 0

3 years ago

Read 2 more answers

A steel beam of mass 1975 kg and length 3 m is attached to the wall with a pin that can rotate freely on its right side. A cable

Nuetrik [128]

Answer:

a) 29062.125 N·m

b) 0 N·m

c) $Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}$

d) T = 11186.02 N

Explanation:

We are given

Beam mass = 1975 kg

Beam length = 3 m

Cable angle = 60° above horizontal

a) We have the formula for torque given as follows;

Torque about the pin = Force × Perpendicular distance of force from pin

Where the force = Force due to gravity or weight, we have

Weight = Mass × Acceleration due to gravity = 1975 × 9.81 = 19374.75 N

Point of action of force = Midpoint for a uniform beam = length/2

∴ Point of action of force = 3/2 = 1.5 m

Torque due to gravity = 19374.75 N × 1.5 m = 29062.125 N·m

b) Torque about the pinned end due to the contact forces between the pin and the beam is given by the following relation;

Since the distance from pin to the contact forces between the pin and the beam is 0, the torque which is force multiplied by perpendicular distance is also 0 N·m

c) To find the expression for the tension force, T we find the sum of the moment forces about the pin as follows

Sum of moments about p is given as follows

∑M = 0 gives;

T·sin(θ) × L= M×L/2×g

Therefore torque due to tension is given by the following expression

$Torque, due \ to \ tension =L\cdot Tsin\theta = \frac{M\cdot L\cdot g}{2}$

d) Plugging in the values in the torque due to tension equation, we have;

$3\times Tsin60 = \frac{1975\times 3\times 9.81}{2} = 29062.125$

Therefore, we make the tension force, T the subject of the formula hence

$T= \frac{29062.125}{3 \times sin(60)} = 11186.02 N$

8 0

3 years ago

A rowboat heads directly across a river at a speed of 3 m/s. Select the correct equations that show that if the river flows at 4

olasank [31]

Answer:

Explanation:

Check attachment for solution

6 0

3 years ago

If a car goes around a corner at a constant 20 miles/hour, does its velocity change?

UNO [17]

Answer:

yes

Explanation:

velocity changes either in magnitude (an increase or decrease in speed) or in direction, or both

3 0

3 years ago

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A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point

Alexus [3.1K]

Answer:

(2.5,0)

Explanation:

The particle can be described by the following equations:

$x=Rsin(-\omega t)+2.5\\y=Rcos(-\omega t)\\\frac{dx}{dt}=-\omega Rcos(-\omega t)\\\frac{dy}{dt}=\omega Rsin(-\omega t)\\\frac{d^2x}{dt^2}=-\omega^2Rsin(-\omega t)\\\frac{d^2y}{dt^2}=-\omega^2Rcos(-\omega t)$

For R = 2.5, ω = 2 and t = 0:

$x=2.5\\y=2.5\\\\\frac{dx}{dt}=-5\\ \frac{d^2y}{dt^2}=-10$

The center of the circle would be at point (2.5,0)

5 0

4 years ago

Rest and Motion are the relative term. why? explain with example(please help me (╥﹏╥))​

Rest and Motion are the relative term. why? explain with example(please help me (╥﹏╥))