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3 years ago

Special relativity questions?

1 answer:

5 0

The right answer for the question that is being asked and shown above is that:
(1) b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
(2) a. the light will reach the front of the rocket before it reaches the back of the rocket.
(3) b. less than Δt
(4) c. the length of your spaceship is getting longer.
(5) c. 1.20c

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A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat

alexdok [17]

Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

Explanation:

We will use law of conservation of energy to find out the velocity

When the potato is at 2.30 m height, it will have potential energy and when the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

Potential energy = Kinetic energy

m×g×h = (1/2) m×v²

m stands for mass

g stands for gravitational constant

h stands for height

v stands for velocity

m×g×h = (1/2) m×v²

0.3×9.8×2.3 = (1/2) .3×v²

v² = 45.08

v = 6.714 m/s

The speed of the potato at lowest point is 6.714 m/s

Part B

The potato is in uniform circular motion so the acceleration is given by

a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration is directly proportional to applied force and inversely proportional to the mass of object

So ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

Tension force - Force due to weight = m×a

T-m×g = m×a

centripetal acceleration formula =v²/r , r = l = length of the string

T = m ×(v²/l) + m×g

v = 6.714 m/s , l = 2.30 m , m = .3 kg Now put values in above equation

T = .3 × (6.714²/2.30) + .3 × 9.8

T = .3 ( 45.08/2.30) + 2.94

T = .3 (19.6) +2.94

T = 5.88 + 2.94

T = 8.82 N

The tension in the string is 8.82 N

5 0

3 years ago

Will mark as brainliest if answered correctly!!!!!!!!!!!!!

Evgen [1.6K]

Answer:

Explanation:

Because...

A= Incideant ray

B= Angle of inciderance

C= angle of reflection

D= reflection ray

8 0

3 years ago

Read 2 more answers

The mean distance of an asteroid from the Sun is 2.98 times that of Earth from the Sun. From Kepler's law of periods, calculate

lutik1710 [3]

Answer:

The asteroid requires 5.14 years to make one revolution around the Sun.

Explanation:

Kepler's third law establishes that the square of the period of a planet will be proportional to the cube of the semi-major axis of its orbit:

$T^{2} = a^{3}$ (1)

Where T is the period of revolution and a is the semi-major axis.

In the other hand, the distance between the Earth and the Sun has a value of $1.50x10^{8} Km$ . That value can be known as well as an astronomical unit (1AU).

But 1 year is equivalent to 1 AU according with Kepler's third law, since 1 year is the orbital period of the Earth.

For the special case of the asteroid the distance will be:

$a = 2.98(1.50x10^{8}Km)$

$a = 4.47x10^{8}Km$

That distance will be expressed in terms of astronomical units:

$4.47x10^{8}Km.\frac{1AU}{1.50x10^{8}Km}$ ⇒ $2.98AU$

Finally, from equation 1 the period T can be isolated:

$T = \sqrt{a^{3}}$

$T = \sqrt{(2.98)^{3}}$

$T = \sqrt{26.463592}$

$T = 5.14AU$

Then, the period can be expressed in years:

$5.14AU.\frac{1yr}{1AU} ⇒ 5.14 yr$

$T = 5.14 yr$

Hence, the asteroid requires 5.14 years to make one revolution around the Sun.

8 0

3 years ago

Which process is represented by the PV diagram?

Reika [66]

Hi!

The answer would be A. Isobaric Process

<h3>Explanation:</h3>

Isobaric process is a process where the pressure inside a system remains unchanged. In the Pressure Volume graph given, you can see that the pressure (y axis) remains constant with an increasing volume ( x axis). An example of this would be heating a container with a movable piston. Now, the degree of pressure is dependent on the frequency of collisions of particles inside a system on the walls. If this frequency changes, the pressure changes (proportionally). In our example, heating a container with a movable piston results in the particles inside the container to gain kinetic energy and move faster, meaning an increased frequency of collisions (higher pressure), but at the system time the increase in pressure results in the piston being pushed outwards, causing the volume of the container to increase. This results in decreased frequency of collision of the particles with the walls of the container (lesser pressure). This results in the a zero net effect on the pressure.

Hope this helps!

3 0

4 years ago

Which of the events below does NOT happen during the G1 phase of the cell cycle

aleksandr82 [10.1K]

Answer:

Could you please add the events

Explanation:

if not I could give a brief explanation of what happens in the phase and you could just eliminate?

6 0

3 years ago