Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
Answer:
0.0196 j
Explanation:
i) The formula for kinetic energy is as follows: 0.5*m*v^2
ii) Since we have all the values all that's left is to plug them into the equation
iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000
iv) All that's left now is to plug it into the equation so:
0.5* (s.45/1000)*(4^2)
v) Lastly we add the unit joules at the end as we're talking about energy
Hope this was useful! :)
Potential energy is mass * gravity * height. (m*g*h).
350 = 17*9.8*h <--350 is its energy, 17kg is its mass, and 9.8 is gravity's acceleration on the object. We now just need to solve for h.
h = 350/(17 * 9.8) = 2.1 meters, which, when rounded to the nearest whole meter, is 2 meters.
The shelf is 2 meters high.
Answer:
The angle of separation is
Explanation:
From the question we are told that
The angle of incidence is ![\theta _ i = 56^o](https://tex.z-dn.net/?f=%5Ctheta%20%20_%20i%20%20%3D%2056%5Eo)
The refractive index of violet light in diamond is ![n_v = 2.46](https://tex.z-dn.net/?f=n_v%20%3D%202.46)
The refractive index of red light in diamond is ![n_r = 2.41](https://tex.z-dn.net/?f=n_r%20%3D%202.41)
The wavelength of violet light is
The wavelength of red light is
Snell's Law can be represented mathematically as
![\frac{sin \theta_i}{sin \theta_r} = n](https://tex.z-dn.net/?f=%5Cfrac%7Bsin%20%5Ctheta_i%7D%7Bsin%20%5Ctheta_r%7D%20%3D%20n)
Where
is the angle of refraction
=> ![sin \theta_r = \frac{sin \theta_i}{n}](https://tex.z-dn.net/?f=sin%20%5Ctheta_r%20%20%3D%20%20%20%5Cfrac%7Bsin%20%5Ctheta_i%7D%7Bn%7D)
Now considering violet light
![sin \theta_r__{v}} = \frac{sin \theta_i}{n_v}](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7Bv%7D%7D%20%20%3D%20%20%20%5Cfrac%7Bsin%20%5Ctheta_i%7D%7Bn_v%7D)
substituting values
![sin \theta_r__{v}} = \frac{sin (56)}{2.46}](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7Bv%7D%7D%20%20%3D%20%20%20%5Cfrac%7Bsin%20%2856%29%7D%7B2.46%7D)
![sin \theta_r__{v}} = 0.337](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7Bv%7D%7D%20%20%3D%20%200.337)
![\theta_r__{v}} = sin ^{-1} (0.337)](https://tex.z-dn.net/?f=%5Ctheta_r__%7Bv%7D%7D%20%20%3D%20%20sin%20%5E%7B-1%7D%20%280.337%29)
![\theta_r__{v}} = 19.69^o](https://tex.z-dn.net/?f=%5Ctheta_r__%7Bv%7D%7D%20%20%3D%20%2019.69%5Eo)
Now considering red light
![sin \theta_r__{R}} = \frac{sin \theta_i}{n_r}](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7BR%7D%7D%20%20%3D%20%20%20%5Cfrac%7Bsin%20%5Ctheta_i%7D%7Bn_r%7D)
substituting values
![sin \theta_r__{R}} = \frac{sin (56)}{2.41}](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7BR%7D%7D%20%20%3D%20%20%20%5Cfrac%7Bsin%20%2856%29%7D%7B2.41%7D)
![sin \theta_r__{R}} = 0.344](https://tex.z-dn.net/?f=sin%20%5Ctheta_r__%7BR%7D%7D%20%20%3D%20%200.344)
![\theta_r__{R}} = sin ^{-1} (0.344)](https://tex.z-dn.net/?f=%5Ctheta_r__%7BR%7D%7D%20%20%3D%20%20sin%20%5E%7B-1%7D%20%280.344%29)
![\theta_r__{R}} = 20.12^o](https://tex.z-dn.net/?f=%5Ctheta_r__%7BR%7D%7D%20%20%3D%2020.12%5Eo)
The angle of separation between the red light and the violet light is mathematically evaluated as
![\Delta \theta = \theta_r__{R}} - \theta_r__{V}}](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D%20%5Ctheta_r__%7BR%7D%7D%20-%20%20%5Ctheta_r__%7BV%7D%7D)
substituting values
![\Delta \theta =20.12 - 19.69](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D20.12%20-%2019.69)
![\Delta \theta = 0.93 ^o](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D%20%200.93%20%5Eo)