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Ulleksa [173]
2 years ago
11

Assume the truck is going at v0 = 25 m/s, and you're 20 m behind the truck. You decide to accelerate at a = 1.0 m/s2 to pass the

truck. To pass safely, you also want to pass the truck by 20 m before moving back to the lane. 1) Estimate the time interval needed to pass a semi-trailer truck on a highway.2) If you are on a two-lane highway, how far away from you must an approaching car be in order for you to safely pass the truck without colliding with the oncoming traffic? Assume the speed of an approaching car is also 25 m/s.
Physics
1 answer:
ehidna [41]2 years ago
4 0

Answer:

I Dont know sorry.......

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Question 2 (5 points)
Harlamova29_29 [7]

Answer:

Fossil fuels store energy from the sun as

8 0
3 years ago
Read 2 more answers
A 2kg blob of putty moving at 4 m/s slams into a 6kg blob of putty at rest what is the speed of the to stick together blobs imme
andrew11 [14]
<h2>Answer</h2>

1m/s

<h2>Explanation</h2>

Given that:

<em>Mass of first blob = 2kg = m1</em>

<em>Velocity of blob = 4m/s = v1</em>

<em>Mass of second blob = 6kg = m2</em>

<em>Velocity of blob = 0m/s = v2</em>

<em />

To find:

<em>Final velocity = Vf</em>

<em />

<em>This question is of inelastic collision which is any collision between objects in which some energy is lost.</em>

<em />

<h3>Formula to be use:</h3><h2>(m1*v1) + (m2*V2) = Vf(m1 + m2)</h2>

(2*4) + (6*0) = Vf(2+6)

8 + 0 = Vf(8)

8 = Vf(8)

Vf = 1 m/s

So the speed of two blobs immediately after colliding = 1 m/s

3 0
3 years ago
Words related to earthquake
Fofino [41]

Answer:

shock, tremble, fault, slip, temblor, upheaval, trembler

undulation

macroseism

seimicity

seismism

Explanation:

3 0
3 years ago
When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup
Xelga [282]

Answer:

E = 169.34 J

Explanation:

First, we need to find the frictional force between the back tire and the road. For that purpose, we use the following formula:

f = μR = μW

f = μmg

where,

f = frictional force = ?

μ = coefficient of friction between tire and road = 0.8

g = 9.8 m/s²

m = mass supported by back tire = (0.5)(90 kg) = 45 kg

Therefore,

f = (0.8)(45 kg)(9.8 m/s²)

f = 352.8 N

Now, for the heat energy we use the formula of work. Because, thermal energy will be equal to work done by frictional force:

E = W = fd

where,

E = Thermal Energy = ?

f = frictional force = 352.8 N

d = displacement = 48 cm = 0.48 m

Therefore,

E = (352.8 N)(0.48 m)

<u>E = 169.34 J</u>

5 0
3 years ago
Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face a
Setler [38]

Answer:

h = 0.288m

Explanation:

Assume

v_1 = Speed of Sue

v_2 = Speed of Chris immediately after the push

Sue's KE = \frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65  

= 331.24

26v_{1}\ ^2 = 331.24

So, v_1 = 3.569

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

m_1v_1 = m_2v_2

52 \times 3.569  = 78 \times v_2

v_2 = 2.380

Chris kt = \frac{1}{2} \times 78 \times 2.380^2

= 220.827

220.827 = mgh

So, h = 0.288m

3 0
3 years ago
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