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Sidana [21]
3 years ago
14

After your school's team wins the regional championship, students go to the dorm roof and start setting off fireworks rockets. T

he rockets explode high in the air and the sound travels out uniformly in all directions. If the sound intensity is 1.62 10-6 W/m2 at a distance of 165 m from the explosion, at what distance from the explosion is the sound intensity half this value
Physics
1 answer:
oksian1 [2.3K]3 years ago
6 0

Answer:

required distance is 233.35 m

Explanation:

Given the data in the question;

Sound intensity I = 1.62 × 10⁻⁶ W/m²

distance r = 165 m

at what distance from the explosion is the sound intensity half this value?

we know that;

Sound intensity I is proportional to 1/(distance)²

i.e

I ∝ 1/r²

Now, let r² be the distance where sound intensity is half, i.e I₂ = I₁/2

Hence,

I₂/I₁ = r₁²/r₂²

1/2 = (165)²/ r₂²

r₂² = 2 × (165)²

r₂² = 2 × 27225

r₂² = 54450

r₂ = √54450

r₂ = 233.35 m

Therefore, required distance is 233.35 m

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Answer:

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Explanation:

given,

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using formula

\vec{F} = q \vec{E}

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Force experienced by the photon in the same field is equal to \vec{F}= -3.52\times 10^{-13}\hat{i}\ N

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Explanation:

hope this helps !!!!

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