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4 years ago

11

In what types of weather do most collisions occur?

2 answers:

Pepsi [2]4 years ago

4 0

Rainy. Most crashes/fatal collisions in adverse weather or on slick pavement

egoroff_w [7]4 years ago

3 0

Rainy and really cold weather because the roads can ice over

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A geologist is trying to determine what time period a layer of rock was formed.

vodka [1.7K]

Answer:

B

Explanation:

You always want to test as many samples as possible

8 0

3 years ago

which of the following types of exercise increase lean body mass?. A.) cardiorespiratory fitness. B.) flexibility. C.) muscular

Sunny_sXe [5.5K]

A lean body mass that the cholesterol level in the body is low and that the excess fats in the body are getting rid off as much as one can. In this case, the exercises A.) cardiorespiratory fitness such as jogging and <span>C.) muscular strength and endurance such as body building, abs routines are employed. Answer is D. both A and C.</span>

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3 years ago

Read 2 more answers

An airplane propeller is 2.68 m in length (from tip to tip) and has a mass of 107 kg. When the airplane's engine is first starte

telo118 [61]

Answer:

a)30.14 rad/s2

b)43.5 rad/s

c)60633 J

d)42 kW

e)84 kW

Explanation:

If we treat the propeller is a slender rod, then its moments of inertia is

$I =\frac{mL^2}{12} = \frac{107*2.68^2}{12} = 64.04 kgm^2$

a. The angular acceleration is Torque divided by moments of inertia:

$\alpha = \frac{T}{I} = \frac{1930}{64.04} = 30.14 rad/s^2$

b. 5 revolution would be equals to $10\pi$ rad, or 31.4 rad. Since the engine just got started

$\omega^2 = 2\alpha\theta = 2*30.14*31.4 = 1893.5$

$\omega = \sqrt{1893.5} = 43.5 rad/s$

c. Work done during the first 5 revolution would be torque times angular displacement:

$W = T*\theta = 1930 * 31.4 = 60633 J$

d. The time it takes to spin the first 5 revolutions is

$t = \frac{\omega}{\alpha} = \frac{43.5}{30.14} = 1.44 s$

The average power output is work per unit time

$P = \frac{W}{t} = \frac{60633}{1.44} = 41991 W$ or 42 kW

e.The instantaneous power at the instant of 5 rev would be Torque times angular speed at that time:

$P_i = T*\omega = 1930*43.5=83983 W$ or 84 kW

7 0

3 years ago

A bucket filled with water has a mass of 54 kg and is hanging from a rope that is wound around a 0.050 m radius stationary cylin

Lubov Fominskaja [6]

Answer:

The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

Explanation:

Given that,

Mass of bucket = 54 kg

Radius = 0.050 m

We need to calculate the magnitude of the torque the bucket produces around the center of the cylinder

Using formula of torque

$\tau=F\times r$

$\tau=mg\times r$

Where, m = mass

g = acceleration due to gravity

r = radius

Put the value into the formula

$\tau=54\times9.8\times0.050$

$\tau=26.46\ N-m$

Hence, The magnitude of the torque the bucket produces around the center of the cylinder is 26.46 N-m.

3 0

3 years ago

What is the net force on this object?

Mariulka [41]

Answer=8N

Explantion:
20-20=0
22-14=8N

5 0

3 years ago